使用MultipartFormDataStreamProvider和ReadAsMultipartAsync

我如何在ApiController使用MultipartFormDataStreamProvider和Request.Content.ReadAsMultipartAsync ？

我用谷歌搜索了一些教程，但是我无法使用任何一个教程，即使用.net 4.5。

这就是我目前得到的：

 public class TestController : ApiController { const string StoragePath = @"T:\WebApiTest"; public async void Post() { if (Request.Content.IsMimeMultipartContent()) { var streamProvider = new MultipartFormDataStreamProvider(Path.Combine(StoragePath, "Upload")); await Request.Content.ReadAsMultipartAsync(streamProvider); foreach (MultipartFileData fileData in streamProvider.FileData) { if (string.IsNullOrEmpty(fileData.Headers.ContentDisposition.FileName)) { throw new HttpResponseException(Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted")); } string fileName = fileData.Headers.ContentDisposition.FileName; if (fileName.StartsWith("\"") && fileName.EndsWith("\"")) { fileName = fileName.Trim('"'); } if (fileName.Contains(@"/") || fileName.Contains(@"\")) { fileName = Path.GetFileName(fileName); } File.Copy(fileData.LocalFileName, Path.Combine(StoragePath, fileName)); } } else { throw new HttpResponseException(Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted")); } } } 

我得到了例外

MIME多部分流的意外结束。 MIME多部分消息未完成。

当await task; 运行。 有没有人知道我做错了什么或者在使用web api的普通asp.net项目中有一个工作示例。

Answer 1

我解决了错误，我不明白这与多部分流的结束有什么关系，但这里是工作代码：

 public class TestController : ApiController { const string StoragePath = @"T:\WebApiTest"; public async Task Post() { if (Request.Content.IsMimeMultipartContent()) { var streamProvider = new MultipartFormDataStreamProvider(Path.Combine(StoragePath, "Upload")); await Request.Content.ReadAsMultipartAsync(streamProvider); foreach (MultipartFileData fileData in streamProvider.FileData) { if (string.IsNullOrEmpty(fileData.Headers.ContentDisposition.FileName)) { return Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted"); } string fileName = fileData.Headers.ContentDisposition.FileName; if (fileName.StartsWith("\"") && fileName.EndsWith("\"")) { fileName = fileName.Trim('"'); } if (fileName.Contains(@"/") || fileName.Contains(@"\")) { fileName = Path.GetFileName(fileName); } File.Move(fileData.LocalFileName, Path.Combine(StoragePath, fileName)); } return Request.CreateResponse(HttpStatusCode.OK); } else { return Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted"); } } } 

Answer 2

首先，您应该在ajax请求标头中将enctype定义为multipart / form-data。

 [Route("{bulkRequestId:int:min(1)}/Permissions")] [ResponseType(typeof(IEnumerable))] public async Task PutCertificatesAsync(int bulkRequestId) { if (Request.Content.IsMimeMultipartContent("form-data")) { string uploadPath = HttpContext.Current.Server.MapPath("~/uploads"); var streamProvider = new MyStreamProvider(uploadPath); await Request.Content.ReadAsMultipartAsync(streamProvider); List messages = new List(); foreach (var file in streamProvider.FileData) { FileInfo fi = new FileInfo(file.LocalFileName); messages.Add(new Pair(fi.FullName, Guid.NewGuid())); } //if (_biz.SetCertificates(bulkRequestId, fileNames)) //{ return Ok(messages); //} //return NotFound(); } return BadRequest(); } } public class MyStreamProvider : MultipartFormDataStreamProvider { public MyStreamProvider(string uploadPath) : base(uploadPath) { } public override string GetLocalFileName(HttpContentHeaders headers) { string fileName = Guid.NewGuid().ToString() + Path.GetExtension(headers.ContentDisposition.FileName.Replace("\"", string.Empty)); return fileName; } }