如何将ImageSource转换为Byte数组？

我使用LeadTools进行扫描。

我想将扫描图像转换为字节。

void twainSession_AcquirePage(object sender, TwainAcquirePageEventArgs e) { ScanImage = e.Image.Clone(); ImageSource source = RasterImageConverter.ConvertToSource(ScanImage, ConvertToSourceOptions.None); } 

如何将ImageSource转换为Byte数组？

Answer 1

除非您明确需要ImageSource对象，否则无需转换为一个。 您可以使用以下代码直接从Leadtools.RasterImage获取包含像素数据的字节数组：

 int totalPixelBytes = e.Image.BytesPerLine * e.Image.Height; byte[] byteArray = new byte[totalPixelBytes]; e.Image.GetRow(0, byteArray, 0, totalPixelBytes); 

请注意，这只为您提供原始像素数据。

如果需要包含完整图像（如JPEG）的内存流或字节数组，则也无需转换为源。 您可以像这样使用Leadtools.RasterCodecs类：

 RasterCodecs codecs = new RasterCodecs(); System.IO.MemoryStream memStream = new System.IO.MemoryStream(); codecs.Save(e.Image, memStream, RasterImageFormat.Jpeg, 24); 

Answer 2

您似乎可以将.ConvertToSource的结果转换为BitmapSource而不是ImageSource。

我不是100％确定这是如何转换为您的情况，但LeadTools的文档显示此VB示例：

  Dim source As BitmapSource Using raster As RasterImage = RasterImageConverter.ConvertFromSource(bitmap, ConvertFromSourceOptions.None) Console.WriteLine("Converted to RasterImage, bits/pixel is {0} and order is {1}", raster.BitsPerPixel, raster.Order) ' Perform image processing on the raster image using LEADTOOLS Dim cmd As New FlipCommand(False) cmd.Run(raster) ' Convert the image back to WPF using default options source = DirectCast(RasterImageConverter.ConvertToSource(raster, ConvertToSourceOptions.None), BitmapSource) End Using 

我认为它应该是这样的

 BitmapSource source = RasterImageConverter.ConvertToSource(ScanImage, ConvertToSourceOptions.None) as BitmapSource; 

然后，您可以使用BitmapSource.CopyPixels复制BitmapSource像素

Answer 3

我使用MemoryStream：

 var source = RasterImageConverter.ConvertToSource(ScanImage, ConvertToSourceOptions.None) as BitmapSource; byte[] data; JpegBitmapEncoder encoder = new JpegBitmapEncoder(); encoder.Frames.Add(BitmapFrame.Create(source)); using (MemoryStream ms = new MemoryStream()) { encoder.Save(ms); data = ms.ToArray(); } 

Answer 4

我使用这个类在WPF中使用Image

 public static class ImageHelper { /// 
 /// ImageSource to bytes /// 
 ///  ///  ///  public static byte[] ImageSourceToBytes(BitmapEncoder encoder, ImageSource imageSource) { byte[] bytes = null; var bitmapSource = imageSource as BitmapSource; if (bitmapSource != null) { encoder.Frames.Add(BitmapFrame.Create(bitmapSource)); using (var stream = new MemoryStream()) { encoder.Save(stream); bytes = stream.ToArray(); } } return bytes; } [DllImport("gdi32.dll")] [return: MarshalAs(UnmanagedType.Bool)] internal static extern bool DeleteObject(IntPtr value); public static BitmapSource GetImageStream(Image myImage) { var bitmap = new Bitmap(myImage); IntPtr bmpPt = bitmap.GetHbitmap(); BitmapSource bitmapSource = System.Windows.Interop.Imaging.CreateBitmapSourceFromHBitmap( bmpPt, IntPtr.Zero, Int32Rect.Empty, BitmapSizeOptions.FromEmptyOptions()); //freeze bitmapSource and clear memory to avoid memory leaks bitmapSource.Freeze(); DeleteObject(bmpPt); return bitmapSource; } /// 
 /// Convert String to ImageFormat /// 
 ///  ///  public static System.Drawing.Imaging.ImageFormat ImageFormatFromString(string format) { if (format.Equals("Jpg")) format = "Jpeg"; Type type = typeof(System.Drawing.Imaging.ImageFormat); BindingFlags flags = BindingFlags.GetProperty; object o = type.InvokeMember(format, flags, null, type, null); return (System.Drawing.Imaging.ImageFormat)o; } /// 
 /// Read image from path /// 
 ///  ///  ///  public static byte[] BytesFromImage(String imageFile, System.Drawing.Imaging.ImageFormat imageFormat) { MemoryStream ms = new MemoryStream(); Image img = Image.FromFile(imageFile); img.Save(ms, imageFormat); return ms.ToArray(); } /// 
 /// Convert image to byte array /// 
 ///  ///  ///  public static byte[] ImageToByteArray(System.Drawing.Image imageIn, System.Drawing.Imaging.ImageFormat imageFormat) { MemoryStream ms = new MemoryStream(); imageIn.Save(ms, imageFormat); return ms.ToArray(); } /// 
 /// Byte array to photo /// 
 ///  ///  public static Image ByteArrayToImage(byte[] byteArrayIn) { MemoryStream ms = new MemoryStream(byteArrayIn); Image returnImage = Image.FromStream(ms); return returnImage; } } 

因此，请尝试不同的方法，并根据需要对此类进行现代化。