AlreadyAllocated调用waveOutOpen错误

private void receiveAudio(object sender) { IPEndPoint senderEP = new IPEndPoint(IPAddress.Any, 0); MemoryStream audioDataStream; BufferedWaveProvider bufferedWaveProvider; //RawSourceWaveStream receivedRawAudioData; byte[] receivedAudioData; waveOutStream = new WaveOut(); while (IsAudioTransferActive) { receivedAudioData = audioUDPClient.Receive(ref senderEP); audioDataStream = new MemoryStream(receivedAudioData); //receivedRawAudioData = new RawSourceWaveStream(audioDataStream, audioFormat); bufferedWaveProvider = new BufferedWaveProvider(audioFormat); //How can I feed "audioDataStream " to "bufferedWaveProvider " waveOutStream.Init(bufferedWaveProvider); waveOutStream.Play(); } waveOutStream.Stop(); waveOutStream.Dispose(); } 

@Mark Heath： – 正如你所说我尝试过使用BufferedWaveProvider但是我如何用“audioDataStream”提供bufferedWaveProvider

Answer 1

您不断在while循环中创建未处理的WaveOut对象，这是问题的一部分。 在这种情况下，最好的方法是创建一个WaveOut对象并使用BufferedWaveProvider提供它。 然后，当音频变为可用时，将其写入BufferedWaveProvider。

Answer 2

使用SineWaveProviders初始化新的WaveOut对象时，我遇到了类似的问题。 我想到使用类似环形列表的东西交换不同提供商的值（频率和幅度），至少在我的情况下，我听不到5个恒定正弦波之上的任何差异。 此外，在我对不同机器的测试中，一次使用6-7个以上的WaveOut对象通常会导致MemoryAllocationError成为振铃列表。 这就是我出来的内容：

 private Queue generators; // constructor public Player() { for (int i = 0; i < 5; i++) { var generator = new SineWaveGenerator(); generator.Amplitude = 0.25f; generators.Enqueue(generator); } } // just a helper method private SineWaveGenerator GetGenerator(int frequency) { return generators.FirstOrDefault(x => x.Frequency == frequency); } private void Play(int frequency) { var generator = GetGenerator(frequency); if (generator == null) { generator = generators.Dequeue(); // get generator from the top of the list generator.Frequency = GetFrequency(key); // modify the generator generators.Enqueue(generator); // and append it to the back } generator.Play(); } private void Stop(int frequency) { var generator = GetGenerator(frequency); if (generator != null) { generator.Stop(); } } 

注意： WaveOut在其构造函数中初始化一个新的WaveOut 。