如何在RichTextBox中找到TextRange（在两个TextPointers之间）

在我的System.Windows.Controls.RichTextBox中，我想找到给定单词的TextRange。 但是，在第一个找到的单词后，它没有给我正确的PositionAtOffset。 第一个是正确的，然后对于下一个找到的单词，位置不正确。 我使用正确的方法吗？

循环遍历listOfWords

Word= listOfWords[j].ToString(); startPos = new TextRange(transcriberArea.Document.ContentStart, transcriberArea.Document.ContentEnd).Text.IndexOf(Word.Trim()); leftPointer = textPointer.GetPositionAtOffset(startPos + 1, LogicalDirection.Forward); rightPointer = textPointer.GetPositionAtOffset((startPos + 1 + Word.Length), LogicalDirection.Backward); TextRange myRange= new TextRange(leftPointer, rightPointer); 

Answer 1

从MSDN上的样本改编的该代码将从指定位置找到单词。

 TextRange FindWordFromPosition(TextPointer position, string word) { while (position != null) { if (position.GetPointerContext(LogicalDirection.Forward) == TextPointerContext.Text) { string textRun = position.GetTextInRun(LogicalDirection.Forward); // Find the starting index of any substring that matches "word". int indexInRun = textRun.IndexOf(word); if (indexInRun >= 0) { TextPointer start = position.GetPositionAtOffset(indexInRun); TextPointer end = start.GetPositionAtOffset(word.Length); return new TextRange(start, end); } } position = position.GetNextContextPosition(LogicalDirection.Forward); } // position will be null if "word" is not found. return null; } 

然后您可以这样使用它：

 string[] listOfWords = new string[] { "Word", "Text", "Etc", }; for (int j = 0; j < listOfWords.Length; j++) { string Word = listOfWords[j].ToString(); TextRange myRange = FindWordFromPosition(x_RichBox.Document.ContentStart, Word); } 

Answer 2

我认为，它也应该有效。

它就像是“查找下一个”列表中的任何项目。

  TextPointer FindWordsFromPosition(TextPointer position, IList words) { var firstPosition = position; while (position != null) { if (position.GetPointerContext(LogicalDirection.Forward) == TextPointerContext.Text) { string textRun = position.GetTextInRun(LogicalDirection.Forward); var indexesInRun = new List(); foreach (var word in words) { var index = textRun.IndexOf(word); if (index == 0) index = textRun.IndexOf(word, 1); indexesInRun.Add(index); } indexesInRun = indexesInRun.Where(i => i != 0 && i != -1).OrderBy(i => i).ToList(); if (indexesInRun.Any()) { position = position.GetPositionAtOffset(indexesInRun.First()); break; } return firstPosition; } else position = position.GetNextContextPosition(LogicalDirection.Forward); } return position; }