存储将在我的应用程序中使用的常量对象的位置

可以说我有一个item ，其中包含字段（属性）

1. 地点
2. 平均值
3. 可用性

我有10-15个items ，我想要预定义其值，或者在某处写入然后加载到要使用的代码中。

哪个是最好的做法呢？

编辑：这些是常量，只是启动参数，在应用程序生命周期中不会被修改。

Answer 1

您可以使用此帮助程序类将List序列化和反序列化为XML文件：

 public static class XmlHelper { // Specifies whether XML attributes each appear on their own line const bool newLineOnAttributes = false; public static bool NewLineOnAttributes { get; set; } /// 
 /// Serializes an object to an XML string, using the specified namespaces. /// 
 public static string ToXml(object obj, XmlSerializerNamespaces ns) { Type T = obj.GetType(); var xs = new XmlSerializer(T); var ws = new XmlWriterSettings { Indent = true, NewLineOnAttributes = newLineOnAttributes, OmitXmlDeclaration = true }; var sb = new StringBuilder(); using (XmlWriter writer = XmlWriter.Create(sb, ws)) { xs.Serialize(writer, obj, ns); } return sb.ToString(); } /// 
 /// Serializes an object to an XML string. /// 
 public static string ToXml(object obj) { var ns = new XmlSerializerNamespaces(); ns.Add("", ""); return ToXml(obj, ns); } /// 
 /// Deserializes an object from an XML string. /// 
 public static T FromXml(string xml) { XmlSerializer xs = new XmlSerializer(typeof(T)); using (StringReader sr = new StringReader(xml)) { return (T)xs.Deserialize(sr); } } /// 
 /// Serializes an object to an XML file. /// 
 public static void ToXmlFile(Object obj, string filePath) { var xs = new XmlSerializer(obj.GetType()); var ns = new XmlSerializerNamespaces(); var ws = new XmlWriterSettings { Indent = true, NewLineOnAttributes = NewLineOnAttributes, OmitXmlDeclaration = true }; ns.Add("", ""); using (XmlWriter writer = XmlWriter.Create(filePath, ws)) { xs.Serialize(writer, obj); } } /// 
 /// Deserializes an object from an XML file. /// 
 public static T FromXmlFile(string filePath) { StreamReader sr = new StreamReader(filePath); try { var result = FromXml(sr.ReadToEnd()); return result; } catch (Exception e) { throw new Exception(e.InnerException.Message); } finally { sr.Close(); } } } 

用法：

 XmlHelper.ToXmlFile(myList, @"c:\folder\file.xml"); var list = XmlHelper.FromXmlFile>(@"c:\folder\file.xml"); 

Answer 2

您的选择将是：

1. XML – 实际上是您的一个标签
2. 数据库
3. 二进制文件

存储对象并将其读取到代码中。

编写XML代码示例：

 public void WriteXML() { Book overview = new Book(); overview.title = "Serialization Overview"; System.Xml.Serialization.XmlSerializer writer = new System.Xml.Serialization.XmlSerializer(typeof(Book)); System.IO.StreamWriter file = new System.IO.StreamWriter( @"c:\temp\SerializationOverview.xml"); writer.Serialize(file, overview); file.Close(); } 

阅读XML代码示例：

 public void Read(string fileName) { XDocument doc = XDocument.Load(fileName); foreach (XElement el in doc.Root.Elements()) { Console.WriteLine("{0} {1}", el.Name, el.Attribute("id").Value); Console.WriteLine(" Attributes:"); foreach (XAttribute attr in el.Attributes()) Console.WriteLine(" {0}", attr); Console.WriteLine(" Elements:"); foreach (XElement element in el.Elements()) Console.WriteLine(" {0}: {1}", element.Name, element.Value); } } 

Answer 3

ApplicationSettings非常适合启动常量。

Answer 4

您所描述的内容听起来像是T4的完美用例

您可以在项目中添加一个读取XML数据的T4模板（在Visual Studio中的设计时），并使用静态内容生成* .cs文件。 如果您需要修改数据，只需修改XML文件并单击解决方案资源管理器中的Transform All Templates按钮。

请记住，如果您需要修改这些内容，则需要重新编译和重新部署应用程序。 如果是这种情况，那么@Mortalus提供的解决方案是最佳选择。

Answer 5

我将使用web.config并将其存储在应用程序设置区域中，然后创建一个将读取这些内容的类将其作为列表进行检索。

以下是它在web配置和C＃代码中的外观。

           public class SomeClass { private string location; private double avgValue; private int usability; public string Location { get { return location; } set { location = value; } } public double AvgValue { get { return avgValue; } set { avgValue = value; } } public int Usability { get { return usability; } set { usability = value; } } } public class Config { public static List Items { get { List result = new List(); for (int i = 1; i <= Convert.ToInt32(WebConfigurationManager.AppSettings["count"]); i++) { SomeClass sClass = new SomeClass(); sClass.AvgValue = Convert.ToDouble(WebConfigurationManager.AppSettings["avgValue_" + i.ToString()]); sClass.Location = WebConfigurationManager.AppSettings["location_" + i.ToString()]; sClass.Usability = Convert.ToInt32(WebConfigurationManager.AppSettings["usability_" + i.ToString()]); } return result; } } 

}