只读XML文件的一部分

  RadheyJang India Software Developer 5 
  ArunaTiwari India SoFtwareCoder 3 
 A  
 NA   

我可以使用下面的代码读取那个Xml。

  XDocument xmlDoc = XDocument.Load(str); var vrresult = from a in xmlDoc.Descendants("People") select new { Name= a.Element("Name").Value, Location= a.Element("Location").Value, Point= a.Element("Point").Value }; GridView1.DataSource = vrresult; GridView1.DataBind(); 

但它正在阅读细节的内容。 我想跳过阅读详细信息元素内的内容 。 请让我知道如何跳过详细内容。

Answer 1

你需要使用XPath …

 using System.Xml.XPath; string xml = @"   RadheyJang India Software Developer 5 
  ArunaTiwari India SoFtwareCoder 3 
 A  
 NA  "; XDocument xmlDoc = XDocument.Parse(xml); var vrresult = from a in xmlDoc.XPathSelectElements("/Peoples/People") select new { Name = a.Element("Name").Value, Location = a.Element("Location").Value, Point = a.Element("Point").Value }; 

Answer 2

  var ele = XElement.Parse(xml); // change to XElement.Load if loading from file var result = ele.Descendants("Section").Zip(ele.Descendannt("Mark"), (s,m) => new {Section = s.Value, Mark = m.Value}); Now you can create your DataTable: var table = new DataTable(); var marks = new DataColumn("Mark"); var sections = new DataColumn("Sections"); table.Columns.Add(marks); table.Columns.Add(sections); foreach (var item in result) { var row = table.NewRow(); row["Mark"] = item.Mark; row["Sections"] = item.Section; table.Rows.Add(row); } 

试试这个代码..

Answer 3

我唯一能想到的是XML不合法：

   *You have an opening People tag here* RadheyJang India Software Developer 5 
 *You create a details tag here*  *You generate the same tag inside of another People tag* ArunaTiwari India SoFtwareCoder 3 
 *Then you close the details tag here* A  
 *Then you close another one, but there is not a second opening detail tag* NA   

我不确定这是否有帮助，但您可能需要考虑修复XML。