如何更改此XML字符串以便XDocument.Parse读取它？
在以下代码中，我将对象序列化为XML 字符串 。
但是当我尝试使用XDocument.Parse将此XML字符串读入XDocument时，它会给我这个错误 ：
根级别的数据无效。
XML是：
1 Jim Jones 23434 更新：这是hex：
![alt text][1] Mod edit – 禁用超链接：指向恶意软件的链接
我该如何处理这个XML，以便它在没有错误的情况下读入XDocument？
using System; using System.Collections.Generic; using System.Xml.Serialization; using System.IO; using System.Xml; using System.Text; using System.Xml.Linq; namespace TestSerialize2342 { class Program { static void Main(string[] args) { List customers = Customer.GetCustomers(); Console.WriteLine("--- Serializing ------------------"); foreach (var customer in customers) { Console.WriteLine("Serializing " + customer.GetFullName() + "..."); string xml = XmlHelpers.SerializeObject(customer); XDocument xdoc = XDocument.Parse(xml); } Console.ReadLine(); } } public static class StringHelpers { public static String UTF8ByteArrayToString(Byte[] characters) { UTF8Encoding encoding = new UTF8Encoding(); String constructedString = encoding.GetString(characters); return (constructedString); } public static Byte[] StringToUTF8ByteArray(String pXmlString) { UTF8Encoding encoding = new UTF8Encoding(); Byte[] byteArray = encoding.GetBytes(pXmlString); return byteArray; } } public static class XmlHelpers { public static string SerializeObject(object o) { MemoryStream ms = new MemoryStream(); XmlSerializer xs = new XmlSerializer(typeof(T)); XmlTextWriter xtw = new XmlTextWriter(ms, Encoding.UTF8); xs.Serialize(xtw, o); ms = (MemoryStream)xtw.BaseStream; return StringHelpers.UTF8ByteArrayToString(ms.ToArray()); } public static T DeserializeObject(string xml) { XmlSerializer xs = new XmlSerializer(typeof(T)); MemoryStream ms = new MemoryStream(StringHelpers.StringToUTF8ByteArray(xml)); XmlTextWriter xtw = new XmlTextWriter(ms, Encoding.UTF8); return (T)xs.Deserialize(ms); } } public class Customer { public int Id { get; set; } public string FirstName { get; set; } public string LastName { get; set; } public string Street { get; set; } public string Location { get; set; } public string ZipCode { get; set; } private int internalValue = 23; public static List GetCustomers() { List customers = new List(); customers.Add(new Customer { Id = 1, FirstName = "Jim", LastName = "Jones", ZipCode = "23434" }); customers.Add(new Customer { Id = 2, FirstName = "Joe", LastName = "Adams", ZipCode = "12312" }); customers.Add(new Customer { Id = 3, FirstName = "Jack", LastName = "Johnson", ZipCode = "23111" }); customers.Add(new Customer { Id = 4, FirstName = "Angie", LastName = "Reckar", ZipCode = "54343" }); customers.Add(new Customer { Id = 5, FirstName = "Henry", LastName = "Anderson", ZipCode = "16623" }); return customers; } public string GetFullName() { return FirstName + " " + LastName + "(" + internalValue + ")"; } } }
回答：
感谢Andras，GetPreamble（）修复它，所以对于其他任何处理此问题的人来说，这里有一个清理BOM的XML的方法：
public static string RemoveUtf8ByteOrderMark(string xml) { string byteOrderMarkUtf8 = Encoding.UTF8.GetString(Encoding.UTF8.GetPreamble()); if (xml.StartsWith(byteOrderMarkUtf8)) { xml = xml.Remove(0, byteOrderMarkUtf8.Length); } return xml; }
这是因为数据在流的开头包含unicode或utf8 BOM标记 。
您需要跳过流中的任何字节顺序标记 – 您可以从System.Text.Encoding.GetPreamble（）方法中识别这些标记。
您可以使用StreamReader将MemoryStream的数据转换为字符串来解决您的问题：
public static string SerializeObject(object o) { using (MemoryStream ms = new MemoryStream()) { XmlSerializer xs = new XmlSerializer(typeof(T)); using (XmlWriter xtw = XmlWriter.Create(ms)) { xs.Serialize(xtw, o); xtw.Flush(); ms.Seek(0, SeekOrigin.Begin); using (StreamReader reader = new StreamReader(ms)) { return reader.ReadToEnd(); } } } }
以上所有内容都是正确的，以下是您应该使用的代码而不是您的代码来跳过BOM：
public static string SerializeObject(object o) { MemoryStream ms = new MemoryStream(); XmlSerializer xs = new XmlSerializer(typeof(T)); //here is my code UTF8Encoding encoding = new UTF8Encoding(false); XmlTextWriter xtw = new XmlTextWriter(ms, encoding); //XmlTextWriter xtw = new XmlTextWriter(ms, Encoding.UTF8); xs.Serialize(xtw, o); ms = (MemoryStream)xtw.BaseStream; return StringHelpers.UTF8ByteArrayToString(ms.ToArray()); }
通过在构造函数中指定false ，您会说“未提供BOM”。 请享用！ =）