如何将WordOpenXML属性转换为System.IO.Packaging.Package？

我一直在尝试使用Visual Studio 2008在C＃中构建Outlook 2010插件。我能够从Microsoft.Office.Interop.Outlook.Inspector对象获取Microsoft.Office.Interop.Outlook.Inspector对象，它表示当前正在编辑的电子邮件。 据我所知，这个DocumentClass也用于其他各种情况（通常用于Microsoft Word扩展，不出所料）。

该类有一个名为WordOpenXML的属性，它似乎是构成.docx包的所有文件的XML表示forms，在将此Word文档另存为.docx将保存到磁盘。

这个属性非常有用的一种方法是它是否可以在内存中转换为System.IO.Packaging.Package对象; 即。 反序列化它。 有谁知道是否有一种简单的方法可以做到这一点，还是我需要编写一些XML解析代码来手动完成它？

Answer 1

我最后修改了一些我在网上找到的代码来创建一个将WordOpenXML转换为Package的方法，该方法保存到磁盘：

 using System; using System.Xml; using System.Xml.XPath; using System.Text; using System.IO; using System.IO.Packaging; // [...] // Call like this: createPackageFromWordOpenXML(wordEditor.WordOpenXML, @"C:\outputFiles\testOut.docx"); /// 
 /// Creates a ZIP package (ie. Word's .docx format) from a WordOpenXML string, which is saved to the file at the path specified. /// 
 /// The WordOpenXML string to get the ZIP package data from. /// The path of the file to save the ZIP package to. private void createPackageFromWordOpenXML(string wordOpenXML, string filePath) { string packageXmlns = "http://schemas.microsoft.com/office/2006/xmlPackage"; Package newPkg = System.IO.Packaging.ZipPackage.Open(filePath, FileMode.Create); try { XPathDocument xpDocument = new XPathDocument(new StringReader(wordOpenXML)); XPathNavigator xpNavigator = xpDocument.CreateNavigator(); XmlNamespaceManager nsManager = new XmlNamespaceManager(xpNavigator.NameTable); nsManager.AddNamespace("pkg", packageXmlns); XPathNodeIterator xpIterator = xpNavigator.Select("//pkg:part", nsManager); while (xpIterator.MoveNext()) { Uri partUri = new Uri(xpIterator.Current.GetAttribute("name", packageXmlns), UriKind.Relative); PackagePart pkgPart = newPkg.CreatePart(partUri, xpIterator.Current.GetAttribute("contentType", packageXmlns)); // Set this package part's contents to this XML node's inner XML, sans its surrounding xmlData element. string strInnerXml = xpIterator.Current.InnerXml .Replace("", "") .Replace("", ""); byte[] buffer = Encoding.UTF8.GetBytes(strInnerXml); pkgPart.GetStream().Write(buffer, 0, buffer.Length); } newPkg.Flush(); } finally { newPkg.Close(); } } 

Answer 2

我将其转换为VB.Net并添加了一个处理二进制附件的peice。 感谢您的出色工作！

 Public Sub createDocXFromWordOpenXML(ByRef sWordOpenXML As String, ByVal sfilePath As String) Dim sPackageXMLNS As String = "http://schemas.microsoft.com/office/2006/xmlPackage" Dim docxPkg As Package Dim xPathDoc As XPathDocument Dim xpNav As XPathNavigator Dim xNSMgnr As XmlNamespaceManager Dim xpPntr As XPathNodeIterator Dim partURI As Uri Dim pkgPart As PackagePart Dim sInnerXML As String Dim bytBuffer As Byte() docxPkg = System.IO.Packaging.ZipPackage.Open(sfilePath, FileMode.Create) Try xPathDoc = New XPathDocument(New StringReader(sWordOpenXML)) xpNav = xPathDoc.CreateNavigator() xNSMgnr = New XmlNamespaceManager(xpNav.NameTable) xNSMgnr.AddNamespace("pkg", sPackageXMLNS) xpPntr = xpNav.Select("//pkg:part", xNSMgnr) While xpPntr.MoveNext() partURI = New Uri(xpPntr.Current.GetAttribute("name", sPackageXMLNS), UriKind.Relative) pkgPart = docxPkg.CreatePart(partURI, xpPntr.Current.GetAttribute("contentType", sPackageXMLNS)) sInnerXML = xpPntr.Current.InnerXml Select Case True Case sInnerXML.Contains("xmlData") sInnerXML = sInnerXML.Replace("", String.Empty) sInnerXML = sInnerXML.Replace("", String.Empty) bytBuffer = Encoding.UTF8.GetBytes(sInnerXML) pkgPart.GetStream().Write(bytBuffer, 0, bytBuffer.Length) Case sInnerXML.Contains("binaryData") sInnerXML = sInnerXML.Replace("", String.Empty) sInnerXML = sInnerXML.Replace("", String.Empty) bytBuffer = Convert.FromBase64String(sInnerXML) pkgPart.GetStream().Write(bytBuffer, 0, bytBuffer.Length) End Select End While docxPkg.Flush() Catch ex As Exception Throw Finally docxPkg.Close() End Try End Sub