如何更正“从其创建的线程以外的线程访问”的错误？

以下代码给出了以下错误。 我想我需要“InvokeRequired”。 但我不明白我该怎么用？

跨线程操作无效：控制’listBox1’从其创建的线程以外的线程访问。

代码：

using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Text; using System.Windows.Forms; using System.Threading; namespace WindowsApplication1 { public partial class Form1 : Form { public Form1() { InitializeComponent(); } protected static DataSet dataset = null; private void Form1_Load(object sender, EventArgs e) { } private void timer1_Tick(object sender, EventArgs e) { SimulationFrameWork.MCSDirector run = new SimulationFrameWork.MCSDirector(); DataSet ds = run.Get(); if (ds.Tables[0].Rows.Count > 0) { for (int i = 0; i < ds.Tables[0].Rows.Count; i++) { if (ds.Tables[0].Rows[i]["result"].ToString() == "0") { dataset = run.Get(int.Parse(ds.Tables[0].Rows[i]["ID"].ToString())); WorkerObject worker = new WorkerObject( int.Parse(dataset.Tables[0].Rows[i]["ID"].ToString()), int.Parse(dataset.Tables[0].Rows[i]["Iteration"].ToString()), listBox1, timer1); Thread thread1 = new Thread(new ThreadStart(worker.start)); thread1.Start(); } } } } } public class WorkerObject { private int id; private int nmax; private ListBox list1; private System.Windows.Forms.Timer timer1; public WorkerObject(int _id, int _nmax, ListBox _list1, System.Windows.Forms.Timer _timer1) { id = _id; nmax = _nmax; list1 = _list1; timer1 = _timer1; } public void start() { timer1.Stop(); int i, idaire, j; double pi = 0.0, x, y; Random rnd = new Random(); for (i = 0; i < 100; i++) { idaire = 0; for (j = 0; j < nmax; j++) { x = rnd.Next(1, 10000) / (double)10000; y = rnd.Next(1, 10000) / (double)10000; if (Math.Pow(x, 2) + Math.Pow(y, 2) " + pi.ToString() + "\n"); System.Threading.Thread.Sleep(100); } SimulationFrameWork.MCSDirector run = new SimulationFrameWork.MCSDirector(); run.Update(id, pi); list1.Items.Add("\n\n islem bitti..."); } } } 

Answer 1

只需封装将文本添加到列表框中另一种方法：

 private void timer1_Tick(object sender, EventArgs e) { // ... AddTextToListBox("\n\n işlem bitti..."); } private void AddTextToListBox(string text) { if(list1.InvokeRequired) { list1.Invoke(new MethodInvoker(AddTextToListBox), new object[] { text }); return; } list1.Items.Add(text); } 

Answer 2

这应该可以帮到你

 private delegate void stringDelegate(string s); private void AddItem(string s) { if (list1.InvokeRequired) { stringDelegate sd = new stringDelegate(AddItem); this.Invoke(sd, new object[] { s }); } else { list1.Items.Add(s); } } 

只需调用AddItem，如果需要，它将使用委托调用add，否则它只是将项目直接添加到框中。

单稳

Answer 3

也可以使用lambda表示法。 所以，而不是：

 formControl.Field = newValue; //Causes error 

尝试：

 Invoke(new Action(() => { formControl.Field = newValue; //No error })); 

Answer 4

在启动线程之前添加此代码：

 //kolay gelsin kardeş ) CheckForIllegalCrossThreadCalls = false; thread1.Start();