反序列化对象列表的问题
我无法反序列化对象列表。 我只能得到一个对象序列化到一个对象但无法获取列表。 我没有得到错误它只返回一个空列表。 这是返回的XML：
1 Building Name Description of Building 这是我的类，我在GetAll方法中反序列化：
[Serializable()] [XmlRoot("location")] public class Building { private string method; [XmlElement("id")] public int LocationID { get; set; } [XmlElement("name")] public string Name { get; set; } [XmlElement("description")] public string Description { get; set; } [XmlElement("mubuildingid")] public string MUBuildingID { get; set; } public List GetAll() { var listBuildings = new List(); var building = new Building(); var request = WebRequest.Create(method) as HttpWebRequest; var response = request.GetResponse() as HttpWebResponse; var streamReader = new StreamReader(response.GetResponseStream()); TextReader reader = streamReader; var serializer = new XmlSerializer(typeof(List), new XmlRootAttribute() { ElementName = "locations" }); listBuildings = (List)serializer.Deserialize(reader); return listBuildings; } }
试试这个：
[XmlRoot("locations")] public class BuildingList { public BuildingList() {Items = new List();} [XmlElement("location")] public List Items {get;set;} }
然后反序列化整个BuildingList对象。
var xmlSerializer = new XmlSerializer(typeof(BuildingList)); var list = (BuildingList)xmlSerializer.Deserialize(xml);
我知道这是一个古老的（呃）问题，但今天我在努力解决这个问题，并找到了一个不需要封装的答案。
假设1：您可以控制源Xml及其构造方式。
假设2：您正在尝试将Xml直接序列化为List对象
- 您必须将Xml中的Root元素命名为
ArrayOfxxx，其中xxx是您的类的名称（或XmlType中指定的名称（请参阅2.）） - 如果希望xml元素具有与该类不同的名称，则应在该类上使用
XmlType。
注意：如果您的类型名称（或类名称）以小写字母开头，则应将第一个字符转换为大写。
示例1 – 没有XmlType
class Program { static void Main(string[] args) { //String containing the xml array of items. string xml = @" -
John Doe -
Martha Stewart "; List- items = null; using (var mem = new MemoryStream(Encoding.Default.GetBytes(xml))) using (var stream = new StreamReader(mem)) { var ser = new XmlSerializer(typeof(List
- )); //Deserialising to List
- items = (List
- )ser.Deserialize(stream); } if (items != null) { items.ForEach(I => Console.WriteLine(I.Name)); } else Console.WriteLine("No Items Deserialised"); } } public class Item { public string Name { get; set; } }
示例2 – 使用XmlType
class Program { static void Main(string[] args) { //String containing the xml array of items. //Note the Array Name, and the Title case on stq. string xml = @" John Doe Martha Stewart "; List- items = null; using (var mem = new MemoryStream(Encoding.Default.GetBytes(xml))) using (var stream = new StreamReader(mem)) { var ser = new XmlSerializer(typeof(List
- )); //Deserialising to List
- items = (List
- )ser.Deserialize(stream); } if (items != null) { items.ForEach(I => Console.WriteLine(I.Name)); } else Console.WriteLine("No Items Deserialised"); } } [XmlType("stq")] public class Item { public string Name { get; set; } }
不确定Building是如何与xml中的位置对应的，但对我来说，如果它们被等同命名则更有意义。 而不是使用List使用LocationList，它变成：
[Serializable()] [XmlRoot("locations")] public class LocationCollection{ [XmlElement("location")] public Location[] Locations {get;set;} } [Serializable()] [XmlRoot("location")] public class Location { [XmlElement("id")] public int LocationID { get; set; } [XmlAttribute("locationtype")] public string LocationType {get;set;} [XmlElement("name")] public string Name { get; set; } [XmlElement("description")] public string Description { get; set; } [XmlElement("mubuildingid")] public string MUBuildingID { get; set; } }
然后，您可以按如下方式反序列化：
var request = WebRequest.Create(method) as HttpWebRequest; var response = request.GetResponse() as HttpWebResponse; var streamReader = new StreamReader(response.GetResponseStream()); TextReader reader = streamReader; var serializer = new XmlSerializer(typeof(LocationCollection), new XmlRootAttribute() { ElementName = "locations" }); var listBuildings = (LocationCollection)serializer.Deserialize(reader); return listBuildings;
我知道，这是一个古老的问题，但遇到类似的问题却遇到了它。 基于@ ricovox的答案以及OP问题的上下文，这是我用来序列化他的xml的模型：
[Serializable, XmlRoot("locations")] public class BuildingList { [XmlArrayItem("location", typeof(Building))] public List locations { get; set; } } [Serializable] public class Building { public int LocationID { get; set; } public string Name { get; set; } public string Description { get; set; } public string MUBuildingID { get; set; } public List GetAll() { ... } }
OP的错误是将列表项创建为根
将[XMLArray]用于集合属性。