WPF自定义按钮使用资源中的几何
有没有办法使用像这样的PathGeometry集合：
路径1 F1 M 170.255,178.837L 170.255,221.158C 170.255,228.917 164.174,230.777 156.745,225.286L 136.003,209.973C 128.572,204.488 128.572,195.512 136.003,190.023L 156.745,174.706C 164.174,169.217 170.255,171.079 170.255,178.837 Z
路径2 F1 M 152.29,174.464L 134.314,187.734C 129.978,190.937 127.589,195.29 127.589,199.994C 127.589,204.7 129.978,209.057 134.314,212.26L 152.29,225.531C 150.333,229.378 145.412,229.52 139.678,225.286L 118.935,209.973C 111.506,204.489 111.506,195.512 118.935,190.022L 139.678,174.708C 145.412,170.475 150.333,170.617 152.29,174.464 Z
并使用它们制作自定义按钮的方式与制作本例中显示的圆形按钮的方式相同？ http://www.wpftutorial.net/Templates.html
该示例涉及覆盖控件模板，如果我想要有许多自定义形状的按钮，这似乎很多工作。 如果我想从资源加载几何点怎么办？
没问题，这段代码会进入参考资料。
M 152.29,174.464L 134.314,187.734C 129.978,190.937 127.589,195.29 127.589,199.994C 127.589,204.7 129.978,209.057 134.314,212.26L 152.29,225.531C 150.333,229.378 145.412,229.52 139.678,225.286L 118.935,209.973C 111.506,204.489 111.506,195.512 118.935,190.022L 139.678,174.708C 145.412,170.475 150.333,170.617 152.29,174.464 Z