如何从c＃中的3×3 Homography矩阵获得旋转，平移，剪切
我计算了3×3单应矩阵，我需要获得旋转，平移，剪切和缩放以将它们用作windows8媒体元素属性中的参数？
请参阅https://math.stackexchange.com/questions/78137/decomposition-of-a-nonsquare-affine-matrix
def getComponents(normalised_homography): '''((translationx, translationy), rotation, (scalex, scaley), shear)''' a = normalised_homography[0,0] b = normalised_homography[0,1] c = normalised_homography[0,2] d = normalised_homography[1,0] e = normalised_homography[1,1] f = normalised_homography[1,2] p = math.sqrt(a*a + b*b) r = (a*e - b*d)/(p) q = (a*d+b*e)/(a*e - b*d) translation = (c,f) scale = (p,r) shear = q theta = math.atan2(b,a) return (translation, theta, scale, shear)