反句全句

我想以反向格式打印字符串：

输入： My name is Archit Patel

输出： Patel Archit is name My 。

我已将下面的内容绑定，但它显示为letaP tihcrA si eman ym 。

 public static string ReverseString(string s) { char[] arr = s.ToCharArray(); Array.Reverse(arr); return new string(arr); } 

Answer 1

您需要将字符串拆分为单词，然后将其反转为而不是反转字符：

 text = String.Join(" ", text.Split(' ').Reverse()) 

在框架3.5中：

 text = String.Join(" ", text.Split(' ').Reverse().ToArray()) 

在框架2.0中：

 string[] words = text.Split(' '); Array.Reverse(words); text = String.Join(" ", words); 

Answer 2

“ 请把这个程序的代码发给我 。”

好的 …

 using System; using System.Linq; class Program { static void Main(string[] args) { string text = "My name is Archit Patel"; Console.WriteLine(string.Join(" ", text.Split(' ').Reverse())); } } 

现在：你学到了什么？

另外，正如Guffa所指出的 ，对于.Net 4.0以下的版本，你需要添加.ToArray()因为string.Join在这些版本中没有正确的重载 。

Answer 3

这应该做你的工作！ 输出：“Patel Archit是我的名字”。

  static void Main(string[] args) { string sentence = "My name is Archit Patel"; StringBuilder sb = new StringBuilder(); string[] split = sentence.Split(' '); for (int i = split.Length - 1; i > -1; i--) { sb.Append(split[i]); sb.Append(" "); } Console.WriteLine(sb); Console.ReadLine(); } 

Answer 4

你可以尝试：

 string[] words = "My name is Archit Patel".Split(new char[] { ' ' }, StringSplitOptions.RemoveEmptyEntries); IEnumerable reverseWords = words.Reverse(); string reverseSentence = String.Join(" ", reverseWords); 

Answer 5

我很欣赏Rob Anderson的回答，但是它会反转完整的句子，只需编辑即可

 string s = "My name is Archit Patel"; string[] words = s.Split(' '); StringBuilder sb = new StringBuilder(); for (int i = words.Length - 1; i >= 0; i--) { sb.Append(words[i]); sb.Append(" "); } Console.WriteLine(sb); 

O / P将是“Patel Archit是我的名字”

Answer 6

使用split方法将其放入数组中

  string[] words = s.Split(' '); 

然后使用array.reverse反转数组

 words = Array.Reverse(words); 

现在，您可以使用for-each循环打印它并添加空格

希望这可以帮助

Answer 7

this.lblStringReverse.Text = Reverse（this.txtString.Text）;

 private int NoOfWhiteSpaces(string s) { char[] sArray = s.ToArray(); int count = 0; for (int i = 0; i < (sArray.Length - 1); i++) { if (sArray[i] == ' ') count++; } return count; } private string Reverse(string s) { char[] sArray = s.ToArray(); int startIndex = 0, lastIndex = 0; string[] stringArray = new string[NoOfWhiteSpaces(s) + 1]; int stringIndex = 0, whiteSpaceCount = 0; for (int x = 0; x < sArray.Length; x++) { if (sArray[x] == ' ' || whiteSpaceCount == NoOfWhiteSpaces(s)) { if (whiteSpaceCount == NoOfWhiteSpaces(s)) { lastIndex = sArray.Length ; } else { lastIndex = x + 1; } whiteSpaceCount++; char[] sWordArray = new char[lastIndex - startIndex]; int j = 0; for (int i = startIndex; i < lastIndex; i++) { sWordArray[j] = sArray[i]; j++; } stringArray[stringIndex] = new string(sWordArray); stringIndex++; startIndex = x+1; } } string result = ""; for (int y = stringArray.Length - 1; y > -1; y--) { if (result == "") { result = stringArray[y]; } else { result = result + ' ' + stringArray[y]; } } return result; } 

Answer 8

  public static string reversewordsInsentence(string sentence) { string output = string.Empty; string word = string.Empty; foreach(char c in sentence) { if (c == ' ') { output = word + ' ' + output; word = string.Empty; } else { word = word + c; } } output = word + ' ' + output; return output; } 

Answer 9

如果你想要非linq解决方案：

 static string ReverseIntact(char[] input) { //char[] input = "dog world car life".ToCharArray(); for (int i = 0; i < input.Length / 2; i++) {//reverse the expression char tmp = input[i]; input[i] = input[input.Length - i - 1]; input[input.Length - i - 1] = tmp; } for (int j = 0, start = 0, end = 0; j <= input.Length; j++) { if (j == input.Length || input[j] == ' ') { end = j - 1; for (; start < end; ) { char tmp = input[start]; input[start] = input[end]; input[end] = tmp; start++; end--; } start = j + 1; } } return new string(input); } 

Answer 10

 namespace Reverse_the_string { class Program { static void Main(string[] args) { // string text = "my name is bharath"; string text = Console.ReadLine(); string[] words = text.Split(' '); int k = words.Length - 1; for (int i = k;i >= 0;i--) { Console.Write(words[i] + " " ); } Console.ReadLine(); } } } 

Answer 11

如果您需要这样做，这是我对面试问题的解决方案。 我使用另外一个字符进行交换。 我假设空间仅用作分隔符。

 using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { StringBuilder sb = new StringBuilder("abcd efg hijk"); Reverse(sb, 0 , sb.Length - 1); Console.WriteLine(sb); ReverseWords(sb); Console.WriteLine(sb); ReverseWordOrder(sb); Console.WriteLine(sb); } static void Reverse(StringBuilder sb, int startIndex, int endIndex) { for(int i = startIndex; i <= (endIndex - startIndex) / 2 + startIndex; i++) { Swap(sb,i, endIndex + startIndex - i); } } private static void Swap(StringBuilder sb, int index1, int index2) { char temp = sb[index1]; sb[index1] = sb[index2]; sb[index2] = temp; } static void ReverseWords(StringBuilder sb) { int startIndex = 0; for (int i = 0; i <= sb.Length; i++) { if (i == sb.Length || sb[i] == ' ') { Reverse(sb, startIndex, i - 1); startIndex = i + 1; } } } static void ReverseWordOrder(StringBuilder sb) { Reverse(sb, 0, sb.Length - 1); ReverseWords(sb); } } } 

Answer 12

这是一个简单的方法

  public static string MethodExercise14Logic(string str) { string[] sentenceWords = str.Split(' '); Array.Reverse(sentenceWords); string newSentence = string.Join(" ", sentenceWords); return newSentence; } 

Answer 13

  string s = "this is a test"; string[] words = s.Split(' '); StringBuilder sb = new StringBuilder(); for (int i = words.Length - 1; i >= 0; i--) { for (int j = words[i].Length -1; j >= 0;j--) { sb.Append(words[i][j]); } sb.Append(" "); } Console.WriteLine(sb);