如何在没有IV的情况下使用AES 128加密和解密？

我目前需要一种方法来加密字符串并使用AES-128对称加密在C＃中解密字节数组。 我找不到办法怎么做，但也许我错过了什么。

Answer 1

导入名称空间

using System; using System.IO; using System.Text; using System.Security.Cryptography; static void Main(string[] args) { string value = "@arifansari300<3>"; string encryptedValue= EncryptDecrypt.Encrypt(value); string decryptedValue = EncryptDecrypt.Decrypt(encryptedValue); } public static string Encrypt(string clearText) { string EncryptionKey = "MAKV2SPBNI99212"; byte[] clearBytes = Encoding.Unicode.GetBytes(clearText); using (Aes encryptor = Aes.Create()) { Rfc2898DeriveBytes pdb = new Rfc2898DeriveBytes(EncryptionKey, new byte[] { 0x49, 0x76, 0x61, 0x6e, 0x20, 0x4d, 0x65, 0x64, 0x76, 0x65, 0x64, 0x65, 0x76 }); encryptor.Key = pdb.GetBytes(32); encryptor.IV = pdb.GetBytes(16); using (MemoryStream ms = new MemoryStream()) { using (CryptoStream cs = new CryptoStream(ms, encryptor.CreateEncryptor(), CryptoStreamMode.Write)) { cs.Write(clearBytes, 0, clearBytes.Length); cs.Close(); } clearText = Convert.ToBase64String(ms.ToArray()); } } return clearText; } public static string Decrypt(string cipherText) { string EncryptionKey = "MAKV2SPBNI99212"; byte[] cipherBytes = Convert.FromBase64String(cipherText); using (Aes encryptor = Aes.Create()) { Rfc2898DeriveBytes pdb = new Rfc2898DeriveBytes(EncryptionKey, new byte[] { 0x49, 0x76, 0x61, 0x6e, 0x20, 0x4d, 0x65, 0x64, 0x76, 0x65, 0x64, 0x65, 0x76 }); encryptor.Key = pdb.GetBytes(32); encryptor.IV = pdb.GetBytes(16); using (MemoryStream ms = new MemoryStream()) { using (CryptoStream cs = new CryptoStream(ms, encryptor.CreateDecryptor(), CryptoStreamMode.Write)) { cs.Write(cipherBytes, 0, cipherBytes.Length); cs.Close(); } cipherText = Encoding.Unicode.GetString(ms.ToArray()); } } return cipherText; }