c＃regex？ 文件中的文本字符串并排序为可搜索的数组？
我有一个文件中的以下文字：
{"players":[{"i":11,"p":0,"a":3186,"n":"IanHx","f":1,"ps":0,"pd":0,"bc":0},{"i":12,"p":0,"a":115,"n":"LoZtamnik","f":1,"ps":0,"pd":0,"bc":0},{"i":58,"p":0,"a":156,"n":"Mr701","f":2,"ps":0,"pd":0,"bc":0},{"i":59,"p":0,"a":156,"n":"B0NE4","f":2,"ps":0,"pd":0,"bc":0},{"i":64,"p":0,"a":324,"n":"5teveJ","f":1,"ps":0,"pd":0,"bc":0}],[....... 我要做的是解析文本，最后得到一个数组，用于{…}之间的每一位数据
所以最终结果如下：
i=11 p=0 a=3186 n=IanHx f=1 ps=0 pd=0 bc=0
然后我可以将它们存储在数据库中
到目前为止，我有这样的事情：
string contents = System.IO.File.ReadAllText("local text file"); //load string contents with text file Regex regex1 = new Regex("\"players\":\\[(?.*)\\]"); //find the players section "players":[.......] Match match1 = regex1.Match(contents); //load match1 Regex regex2 = new Regex("{(?([^}]*))}"); // then break down each player {....} MatchCollection match2 = regex2.Matches(match1.Groups["players"].Value); //load match2 with each player
然后我陷入困境试图以某种方式拆分匹配字符串[]，看着它可能会过度复杂吗？
指向数据解析的更简单解决方案的任何指针
谢谢
您文件中包含的数据采用JSON格式。 如果格式正确，JSON很容易阅读。 如果我重新格式化您的输入，结构会变得更清晰：
{ "players": [ { "i": 11, "p": 0, "a": 3186, "n": "IanHx", "f": 1, "ps": 0, "pd": 0, "bc": 0 }, { "i": 12, "p": 0, "a": 115, "n": "LoZtamnik", "f": 1, "ps": 0, "pd": 0, "bc": 0 }, { "i": 58, "p": 0, "a": 156, "n": "Mr701", "f": 2, "ps": 0, "pd": 0, "bc": 0 }, { "i": 59, "p": 0, "a": 156, "n": "B0NE4", "f": 2, "ps": 0, "pd": 0, "bc": 0 }, { "i": 64, "p": 0, "a": 324, "n": "5teveJ", "f": 1, "ps": 0, "pd": 0, "bc": 0 } ] }
在JSON中， [ ]包含的任何内容表示集合， { }包含的任何内容表示对象。 所以，你可以看到你有一个叫做players的集合，其中包含5个对象（因为players [ ]内有5对{ } ），每个属性有8个属性。 如果您在C＃术语中考虑这些，那么您将拥有一个名为Player且具有这8个属性的类，以及一个List来保存每个Player实例。 然后你就可以获取JSON数据并将它们反序列化为它们的C＃对应物，这样你就可以按照你认为合适的方式对它们进行操作，正如Dave Bish在他的回答中指出的那样。
有一种非常简单的方法可以自动从JSON数据创建C＃类：
- 在项目中创建一个新类，根据需要命名并清除所有内容
- 复制JSON数据（来自我的示例或您的示例）
- 返回到该类，然后单击
Edit -> Paste Special -> Paste JSON As Classes
瞧。 Visual Studio让你回来了。 您现在应该看到以下内容：
public class Rootobject { public Player[] players { get; set; } } public class Player { public int i { get; set; } public int p { get; set; } public int a { get; set; } public string n { get; set; } public int f { get; set; } public int ps { get; set; } public int pd { get; set; } public int bc { get; set; } }
然后，您可以做任何最适合您场景的事情，例如添加System.Collections.Generic命名空间，这样您就可以使Player[]成为List 。
现在，要操纵JSON数据并将它们反序列化为我们刚刚创建的C＃类，您可以使用优秀的Json.NET库。 要添加它，请右键单击解决方案资源"Manage NuGet Packages..."应用程序，然后单击"Manage NuGet Packages..." 。 在搜索框中键入"Json.NET"并进行安装。
一旦你有了它，添加Newtonsoft.Json命名空间，你很高兴。 您现在可以使用Json.NET的DeserializeObject方法将JSON数据反序列化为我们创建的C＃类：
//i've hardcoded the JSON data here, obviously you would extract them from your file var jsonData = @"{""players"":[{""i"":11,""p"":0,""a"":3186,""n"":""IanHx"",""f"":1,""ps"":0,""pd"":0,""bc"":0},{""i"":12,""p"":0,""a"":115,""n"":""LoZtamnik"",""f"":1,""ps"":0,""pd"":0,""bc"":0},{""i"":58,""p"":0,""a"":156,""n"":""Mr701"",""f"":2,""ps"":0,""pd"":0,""bc"":0},{""i"":59,""p"":0,""a"":156,""n"":""B0NE4"",""f"":2,""ps"":0,""pd"":0,""bc"":0},{""i"":64,""p"":0,""a"":324,""n"":""5teveJ"",""f"":1,""ps"":0,""pd"":0,""bc"":0}]}"; //deserialize the JSON into the C# class we created and store it in myPlayerData var myPlayerData = JsonConvert.DeserializeObject(jsonData); //you can now do stuff such as.. foreach(Player player in myPlayerData.players) { MessageBox.Show(string.Format("Player {0} has an i of {1} and an a of {2}", player.n, player.i, player.a)); }
你试图用NuGet的Json.Net反序列化它会好得多
定义一些类以匹配您的文件结构：
public class Root { public List players {get; set;} } public class Something { public string i {get; set;} public string p {get; set;} public string a {get; set;} public string n {get; set;} public string f {get; set;} public string ps {get; set;} public string pd {get; set;} public string bc {get; set;} }
使用Json.Net来处理：
var json = @"{""players"":[{""i"":11,""p"":0,""a"":3186,""n"":""IanHx"",""f"":1,""ps"":0,""pd"":0,""bc"":0},{""i"":12,""p"":0,""a"":115,""n"":""LoZtamnik"",""f"":1,""ps"":0,""pd"":0,""bc"":0},{""i"":58,""p"":0,""a"":156,""n"":""Mr701"",""f"":2,""ps"":0,""pd"":0,""bc"":0},{""i"":59,""p"":0,""a"":156,""n"":""B0NE4"",""f"":2,""ps"":0,""pd"":0,""bc"":0},{""i"":64,""p"":0,""a"":324,""n"":""5teveJ"",""f"":1,""ps"":0,""pd"":0,""bc"":0}]}"; var data = JsonConvert.DeserializeObject(json);