使用带有RSA C#的非对称算法私钥和公钥

我有两个包含RSA Private和RSA公钥的AsymmetricAlgorithm对象。 从Windows-MY密钥库中检索私钥,从用户证书中检索公钥。 如何使用这些密钥和RSACryptoServiceProvider在C#中使用RSA算法加密数据? 换句话说,我如何指定我想使用已有的密钥?

#region "RSA Encrypt/Decrypt" public string RSAEncrypt(string str, string publicKey) { //---Creates a new instance of RSACryptoServiceProvider--- try { RSACryptoServiceProvider RSA = new RSACryptoServiceProvider(); //---Loads the public key--- RSA.FromXmlString(publicKey); byte[] EncryptedStr = null; //---Encrypts the string--- EncryptedStr = RSA.Encrypt(ASCII.GetBytes(str), false); //---Converts the encrypted byte array to string--- int i = 0; System.Text.StringBuilder s = new System.Text.StringBuilder(); for (i = 0; i <= EncryptedStr.Length - 1; i++) { //Console.WriteLine(EncryptedStr(i)) if (i != EncryptedStr.Length - 1) { s.Append(EncryptedStr[i] + " "); } else { s.Append(EncryptedStr[i]); } } return s.ToString(); } catch (Exception err) { Interaction.MsgBox(err.ToString()); } } public string RSADecrypt(string str, string privateKey) { try { //---Creates a new instance of RSACryptoServiceProvider--- RSACryptoServiceProvider RSA = new RSACryptoServiceProvider(); //---Loads the private key--- RSA.FromXmlString(privateKey); //---Decrypts the string--- byte[] DecryptedStr = RSA.Decrypt(HexToByteArr(str), false); //---Converts the decrypted byte array to string--- System.Text.StringBuilder s = new System.Text.StringBuilder(); int i = 0; for (i = 0; i <= DecryptedStr.Length - 1; i++) { //Console.WriteLine(DecryptedStr(i)) s.Append(System.Convert.ToChar(DecryptedStr[i])); } //Console.WriteLine(s) return s.ToString(); } catch (Exception err) { Interaction.MsgBox(err.ToString()); } } #endregion 

公钥(arg)应如下所示: <模数> yNi8BvATA77f + / 6cU6z [...] 9VULgU = <指数> AQAB

私钥(arg)应如下所示: <模数> yNi8BvATA77f + / 6cU6z [...] 9VULgU = <指数> AQAB

8ZlZPmko3sam9pvD / l [...] ba0MWLjj9dyUMvmTQ6L8m9IQ == 1NGHjXyEa9SjUwY [...] v + op2YyyglMeK / Gt5SL0v6xqQZQ == LpjE / aSKnWzzBt1E [...] i5f63Ak9wVG3ZPnwVDwefNkMAQ == qAgb8AGNiJom [ ...] 8x3qaD3wx + UbnM5v3aE5Q == fQ4 + 7r3Nmgvz113L [...] uJqEgCNzw == B4n7JNeGHzHe / nqEK [...] GaOBtuz0QTgE =