使用Umbraco Base返回Json而不是XML
我有一个.NET方法，可以为我的数据库添加一个新成员。 它通过AJAX请求完成此操作。 我有这个工作正常，但是我在返回正确的响应消息时遇到问题，因此我可以向用户打印正确的消息。
我的方法目前看起来像这样：
public static string MemberRegister(int process) { //here we find form values posted to the current page HttpRequest post = HttpContext.Current.Request; //get values from ajax URL var name = post["name"]; var email = post["email"]; var username = post["username"]; var password = post["password"]; //check if email exists if (Member.GetMemberFromEmail(email) == null) { MemberType userMemberType = new MemberType(1111); //id of membertype 'demo' Member newMember = Member.MakeNew(name, userMemberType, new umbraco.BusinessLogic.User(0)); newMember.AddGroup(MemberGroup.GetByName("Active").Id); newMember.Email = email; newMember.Password = password; newMember.LoginName = username; newMember.Save(); return "success"; } else { return "emailError"; } } 我的Ajax代码如下：
// submit $registerForm.submit(function() { $loader.show(); jQuery.ajax({ url: "/processform.aspx", type: "POST", data: $(this).serialize() }).complete(function( response ) { alert(response.responseText); if( response.responseText === "success" ) { $registerSuccess.fadeIn(); } elseif( response.responseText === "emailError" ) { $registerEmailError.fadeIn(); } else { $registerError.slideDown(); } $loader.hide(); }); return false; });
例如，如果所有成员都存在，则返回响应：
emailError
我只是想让它返回emailError而不是值标签。 我该怎么做呢？
提琴手（原始）：
HTTP/1.1 200 OK Content-Type: text/xml; charset=utf-8 Vary: Accept-Encoding Server: Microsoft-IIS/7.5 X-Powered-By: ASP.NET Date: Sun, 25 Mar 2012 20:59:54 GMT Content-Length: 25 emailError POST http://domain.com/base/Forms/MemberRegister/process.aspx HTTP/1.1 Host: domain.com Connection: keep-alive Content-Length: 125 Origin: http://domain.com X-Requested-With: XMLHttpRequest User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/535.11 (KHTML, like Gecko) Chrome/17.0.963.79 Safari/535.11 Content-Type: application/json; charset=UTF-8 Accept: application/json, text/javascript, */*; q=0.01 Referer: http://domain/register.aspx Accept-Encoding: gzip,deflate,sdch Accept-Language: en-GB,en-US;q=0.8,en;q=0.6 Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 Cookie: ASP.NET_SessionId=ys4mmhsn2mpqcpja1iyjg04m; UMB_UPDCHK=1; __utma=256732567.15732944.1331581910.1332617890.1332627641.11; __utmc=256732567; __utmz=256732567.1331581910.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); UMB_UCONTEXT=12621b40-16fe-4422-a027-cf4fa68fe03d; __utma=176230262.1311679778.1332368941.1332694687.1332708163.12; __utmb=176230262.3.10.1332708163; __utmc=176230262; __utmz=176230262.1332368941.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none) __VIEWSTATE=%2FwEPDwUENTM4MWRkEytUM47m6NUA6dpfOudOh9t51j6okfG%2BQhu4Em%2B26KU%3D&name=ppp&email=ppp&username=ppp&username=ppp
谢谢罗伯特
以下是如何使用Umbraco Base返回JSON对象的一个很好的示例：
/* Be sure to add References to: * * umbraco.dll * System.Web.dll * System.Web.Extensions.dll */ using System.Web; using System.Web.Script.Serialization; using umbraco.presentation.umbracobase; namespace CoB.Umb.Base.Example { [RestExtension("Example")] public class Example { [RestExtensionMethod(returnXml = false, allowAll = true)] public static void Get() { string json = ""; var person = new { firstName = "John", lastName = "Doe" }; json = new JavaScriptSerializer().Serialize(person); HttpContext.Current.Response.ContentType = "application/json"; HttpContext.Current.Response.Write(json); } } }
和javascript：
$.getJSON('/base/Example/Get', function (data) { alert("Hey, " + data.firstName + " " + data.lastName); });
这个站点非常适合帮助ASP.NET jQuery Ajax调用，特别是这篇文章
Adrian Iftode的答案是正确的，但您不需要在服务器上设置响应格式。 如果您要求JSON，服务器将自动编码为。 如果您有多个服务调用Web服务并且您需要对它们进行不同的编码，这很方便。
$.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "WebService.asmx/WebMethodName", data: "{}", dataType: "json" });
当我开始这样做时，我也发现这篇文章很有帮助。 它提供了一些将所有$ .ajax调用移动到一个地方的代码。
// *** Service Calling Proxy Class function serviceProxy(serviceUrl){ var _I = this; this.serviceUrl = serviceUrl; // *** Call a wrapped object this.invoke = function(method,data,callback,error,bare) { // *** Convert input data into JSON - REQUIRES Json2.js var json = JSON2.stringify(data); // *** The service endpoint URL var url = _I.serviceUrl + method; $.ajax( { url: url, data: json, type: "POST", processData: false, contentType: "application/json", timeout: 10000, dataType: "text", // not "json" we'll parse success: function(res) { if (!callback) return; // *** Use json library so we can fix up MS AJAX dates var result = JSON2.parse(res); // *** Bare message IS result if (bare) { callback(result); return; } // *** Wrapped message contains top level object node // *** strip it off for(var property in result) { callback( result[property] ); break; } }, error: function(xhr) { if (!error) return; if (xhr.responseText) { var err = JSON2.parse(xhr.responseText); if (err) error(err); else error( { Message: "Unknown server error." }) } return; } }); }} // *** Create a static instance var Proxy = new serviceProxy("JsonStockService.svc/"); // *** Call the webservice Proxy.invoke("GetStockQuote",{ symbol: symbol },function(result){...}, onPageError);
您可能需要修饰该方法以返回Json
[WebMethod] [ScriptMethod(ResponseFormat = ResponseFormat.Json)] public static string MemberRegister(int process) complete(function( response ) { if (response.d == "success") { // } }
编辑
jQuery.ajax({ url: "/processform.aspx", type: "POST", contentType: "application/json; charset=utf-8", dataType: "json", data: $(this).serialize() })..
终于想通了！
我需要在我的一个类调用中添加“returnXml = false”。