将块中的文件发送到HttpHandler
我正在尝试将块中的文件发送到HttpHandler但是当我在HttpContext中收到请求时，inputStream为空。
所以a：发送时我不确定我的HttpWebRequest是否有效而b：接收时我不知道如何在HttpContext中检索流
任何帮助非常感谢！
这是我如何从客户端代码发出请求：
private void Post(byte[] bytes) { HttpWebRequest req = (HttpWebRequest)HttpWebRequest.Create("http://localhost:2977/Upload"); req.Method = "POST"; req.ContentType = "application/x-www-form-urlencoded"; req.SendChunked = true; req.Timeout = 400000; req.ContentLength = bytes.Length; req.KeepAlive = true; using (Stream s = req.GetRequestStream()) { s.Write(bytes, 0, bytes.Length); s.Close(); } HttpWebResponse res = (HttpWebResponse)req.GetResponse(); } 这就是我在HttpHandler中处理请求的方式：
public void ProcessRequest(HttpContext context) { Stream chunk = context.Request.InputStream; //it's empty! FileStream output = new FileStream("C:\\Temp\\myTempFile.tmp", FileMode.Append); //simple method to append each chunk to the temp file CopyStream(chunk, output); }
我怀疑你将它作为表格编码上传可能会令人困惑。 但这不是你发送的东西（除非你在掩饰某些东西）。 这种MIME类型是否真的正确？
数据有多大？ 你需要分块上传吗？ 某些服务器在单个请求中可能不喜欢这样; 我很想通过WebClient.UploadData使用多个简单的请求。
我正在尝试相同的想法，并通过Post httpwebrequest成功发送文件。 请参阅以下代码示例
private void ChunkRequest(string fileName,byte[] buffer) { //Request url, Method=post Length and data. string requestURL = "http://localhost:63654/hello.ashx"; HttpWebRequest request = (HttpWebRequest)WebRequest.Create(requestURL); request.Method = "POST"; request.ContentType = "application/x-www-form-urlencoded"; // Chunk(buffer) is converted to Base64 string that will be convert to Bytes on the handler. string requestParameters = @"fileName=" + fileName + "&data=" + HttpUtility.UrlEncode( Convert.ToBase64String(buffer) ); // finally whole request will be converted to bytes that will be transferred to HttpHandler byte[] byteData = Encoding.UTF8.GetBytes(requestParameters); request.ContentLength = byteData.Length; Stream writer = request.GetRequestStream(); writer.Write(byteData, 0, byteData.Length); writer.Close(); // here we will receive the response from HttpHandler StreamReader stIn = new StreamReader(request.GetResponse().GetResponseStream()); string strResponse = stIn.ReadToEnd(); stIn.Close(); }
我已经在博客上发表过这篇文章，你在这里看到整个HttpHandler / HttpWebRequestposthttp://aspilham.blogspot.com/2011/03/file-uploading-in-chunks-using.html我希望这会有所帮助