为什么来自线程教程的MSDN示例崩溃？

来自MSDN “线程教程”的示例4
以下代码错误出现在“—错误就在这里—”的行中。
怎么了？

using System; using System.Threading; public class MutexSample { static Mutex gM1; static Mutex gM2; const int ITERS = 100; static AutoResetEvent Event1 = new AutoResetEvent(false); static AutoResetEvent Event2 = new AutoResetEvent(false); static AutoResetEvent Event3 = new AutoResetEvent(false); static AutoResetEvent Event4 = new AutoResetEvent(false); public static void Main(String[] args) { Console.WriteLine("Mutex Sample ..."); // Create Mutex initialOwned, with name of "MyMutex". gM1 = new Mutex(true, "MyMutex"); // Create Mutex initialOwned, with no name. gM2 = new Mutex(true); Console.WriteLine(" - Main Owns gM1 and gM2"); AutoResetEvent[] evs = new AutoResetEvent[4]; evs[0] = Event1; // Event for t1 evs[1] = Event2; // Event for t2 evs[2] = Event3; // Event for t3 evs[3] = Event4; // Event for t4 MutexSample tm = new MutexSample(); Thread thread1 = new Thread(new ThreadStart(tm.t1Start)); Thread thread2 = new Thread(new ThreadStart(tm.t2Start)); Thread thread3 = new Thread(new ThreadStart(tm.t3Start)); Thread thread4 = new Thread(new ThreadStart(tm.t4Start)); thread1.Start(); // Does Mutex.WaitAll(Mutex[] of gM1 and gM2) thread2.Start(); // Does Mutex.WaitOne(Mutex gM1) thread3.Start(); // Does Mutex.WaitAny(Mutex[] of gM1 and gM2) thread4.Start(); // Does Mutex.WaitOne(Mutex gM2) Thread.Sleep(2000); Console.WriteLine(" - Main releases gM1"); gM1.ReleaseMutex(); // t2 and t3 will end and signal Thread.Sleep(1000); Console.WriteLine(" - Main releases gM2"); gM2.ReleaseMutex(); // t1 and t4 will end and signal // Waiting until all four threads signal that they are done. WaitHandle.WaitAll(evs); Console.WriteLine("... Mutex Sample"); } public void t1Start() { Console.WriteLine("t1Start started, Mutex.WaitAll(Mutex[])"); Mutex[] gMs = new Mutex[2]; gMs[0] = gM1; // Create and load an array of Mutex for WaitAll call gMs[1] = gM2; Mutex.WaitAll(gMs); // Waits until both gM1 and gM2 are released Thread.Sleep(2000); Console.WriteLine("t1Start finished, Mutex.WaitAll(Mutex[]) satisfied"); Event1.Set(); // AutoResetEvent.Set() flagging method is done } public void t2Start() { Console.WriteLine("t2Start started, gM1.WaitOne( )"); gM1.WaitOne(); // Waits until Mutex gM1 is released ---errors is here--- Console.WriteLine("t2Start finished, gM1.WaitOne( ) satisfied"); Event2.Set(); // AutoResetEvent.Set() flagging method is done } public void t3Start() { Console.WriteLine("t3Start started, Mutex.WaitAny(Mutex[])"); Mutex[] gMs = new Mutex[2]; gMs[0] = gM1; // Create and load an array of Mutex for WaitAny call gMs[1] = gM2; Mutex.WaitAny(gMs); // Waits until either Mutex is released Console.WriteLine("t3Start finished, Mutex.WaitAny(Mutex[])"); Event3.Set(); // AutoResetEvent.Set() flagging method is done } public void t4Start() { Console.WriteLine("t4Start started, gM2.WaitOne( )"); gM2.WaitOne(); // Waits until Mutex gM2 is released Console.WriteLine("t4Start finished, gM2.WaitOne( )"); Event4.Set(); // AutoResetEvent.Set() flagging method is done } } 

Answer 1

在等待Mutex之后，您必须使用它来释放它

 Mutex.ReleaseMutex() 

在线程退出之前。

修复了t1start – t4start

 public void t1Start() { Console.WriteLine("t1Start started, Mutex.WaitAll(Mutex[])"); Mutex[] gMs = new Mutex[2]; gMs[0] = gM1; // Create and load an array of Mutex for WaitAll call gMs[1] = gM2; Mutex.WaitAll(gMs); // Waits until both gM1 and gM2 are released Thread.Sleep(2000); Console.WriteLine("t1Start finished, Mutex.WaitAll(Mutex[]) satisfied"); Event1.Set(); // AutoResetEvent.Set() flagging method is done gM1.ReleaseMutex(); gM2.ReleaseMutex(); } public void t2Start() { Console.WriteLine("t2Start started, gM1.WaitOne( )"); gM1.WaitOne(); // Waits until Mutex gM1 is released ---errors is here--- Console.WriteLine("t2Start finished, gM1.WaitOne( ) satisfied"); gM1.ReleaseMutex(); Event2.Set(); // AutoResetEvent.Set() flagging method is done } public void t3Start() { Console.WriteLine("t3Start started, Mutex.WaitAny(Mutex[])"); Mutex[] gMs = new Mutex[2]; gMs[0] = gM1; // Create and load an array of Mutex for WaitAny call gMs[1] = gM2; int result = Mutex.WaitAny(gMs); // Waits until either Mutex is released gMs[result].ReleaseMutex(); Console.WriteLine("t3Start finished, Mutex.WaitAny(Mutex[])"); Event3.Set(); // AutoResetEvent.Set() flagging method is done } public void t4Start() { Console.WriteLine("t4Start started, gM2.WaitOne( )"); gM2.WaitOne(); // Waits until Mutex gM2 is released Console.WriteLine("t4Start finished, gM2.WaitOne( )"); Event4.Set(); // AutoResetEvent.Set() flagging method is done gM2.ReleaseMutex(); }