LINQ：按最常见值排序
我正在尝试在c＃中创建一个“有序”对象列表，其中列表将按ImdbId属性中最常见的值排序。 我没有使用数据库我从列表中获取远程api的结果，我只需要以优雅的方式对列表进行排序。
class Movie { String ImdbId {get; set; } String Name {get;set;} ... more properties } 未排序列表的示例：
imdbId | Name 698649 | "Sex and the City" Models and Mortals 698669 | "Sex and the City" The Awful Truth 698649 | "Sex and the City" Models and Mortals 698649 | "Sex and the City" Models and Mortals 698679 | "Sex and the City" The Drought 698697 | "Sex and the City" Valley of the Twenty-Something Guys 1568911 | War Horse
排序应该如下所示：
imdbId | Name 698649 | "Sex and the City" Models and Mortals 698649 | "Sex and the City" Models and Mortals 698649 | "Sex and the City" Models and Mortals 698669 | "Sex and the City" The Awful Truth 698679 | "Sex and the City" The Drought 698697 | "Sex and the City" Valley of the Twenty-Something Guys 1568911 | War Horse
这是另一个例子：
imdbId | Name 1568911 | War Horse 698690 | "Sex and the City" The Turtle and the Hare 698653 | "Sex and the City" Old Dogs, New Dicks 698690 | "Sex and the City" The Turtle and the Hare 698690 | "Sex and the City" The Turtle and the aHare 1000774 | Sex and the City
排序应该如下所示：
imdbId | Name 698690 | "Sex and the City" The Turtle and the Hare 698690 | "Sex and the City" The Turtle and the Hare 698690 | "Sex and the City" The Turtle and the aHare 698653 | "Sex and the City" Old Dogs, New Dicks 1000774 | Sex and the City 1568911 | War Horse
我试着追随但没有运气。
List newList = List .OrderByDescending(a => a.ImdbId) .ThenByDescending(a => a.ImdbId.Count()) .ToList();
知道如何用lambda或LINQ实现这个目标吗？
试试这个：
var newList = List.GroupBy(x=>x.ImdbId) .OrderByDescending(g=>g.Count()) .SelectMany(g=>g).ToList();