RestSharp序列化/反序列化命名转换

我正在尝试使用RestSharp包装Plivo API（ 是的，我知道它已经完成 ）。

但是，我找不到将API命名约定转换为我自己的方法，例如：

“呼叫”（ https://www.plivo.com/docs/api/call/#make-an-outbound-call ）至少需要：

to ， from和answer_url参数。

这些参数也区分大小写。

我希望能够提供一个CallRequest类，包装我首选命名约定中所需的数据，然后以某种方式在RestSharp序列化之前转换它们。

例：

 public class CallRequest { /// 
 /// The phone number to be used as the caller id (with the country code).For eg, a USA caller id number could be, 15677654321, with '1' for the country code. /// 
 public string From { get; set; } /// 
 /// The regular number(s) or sip endpoint(s) to call. Regular number must be prefixed with country code but without the + sign). For eg, to dial a number in the USA, the number could be, 15677654321, with '1' for the country code. Multiple numbers can be sent by using a delimiter. For eg 15677654321<12077657621<12047657621. Sip endpoints must be prefixed with sip: Eg, sip:[e-mail]. To make bulk calls, the delimiter < is used. For eg. 15677654321<15673464321<sip:[e-mail] Yes, you can mix regular numbers and sip endpoints. /// 
 public string To { get; set; } /// 
 /// The URL invoked by Plivo when the outbound call is answered. /// 
 public string AnswerUrl { get; set; } } 

然后，这些数据将在以下函数中转换为Plivo的约定：

  private T Execute(IRestRequest request) where T : new() { var client = new RestClient { BaseUrl = new Uri(BaseUrl), Authenticator = new HttpBasicAuthenticator(_accountId, _authToken), UserAgent = "PlivoSharp" }; request.AddHeader("Content-Type", "application/json"); request.AddParameter("auth_id", _accountId, ParameterType.UrlSegment); request.RequestFormat = DataFormat.Json; client.AddHandler("application/json", new JsonDeserializer()); var response = client.Execute(request); if (response.ErrorException == null) return response.Data; const string message = "Error retrieving response. Check inner details for more info."; var plivoException = new ApplicationException(message, response.ErrorException); throw plivoException; } public CallResponse MakeCall(CallRequest callRequest) { var request = new RestRequest { RequestFormat = DataFormat.Json, Resource = "Account/{auth_id}/Call/", Method = Method.POST }; //SOMEHOW TRANSLATE THE PROPERTIES INTO THE DATA BELOW request.AddBody(new { to = "17#####", from = "18#####", answer_url = "http://m------.xml" }); return Execute(request); } 

Answer 1

不幸的是，看起来好像JSON属性重命名不是在RestSharp中开箱即用的。 你有几个选择：

1. 从https://github.com/restsharp/RestSharp下载Restsharp并自行重建，启用编译器选项SIMPLE_JSON_DATACONTRACT 。 然后，您将能够使用数据协定属性重命名属性。 有关更多信息，请参阅此处： RestSharp JsonDeserializer，标识符中包含特殊字符

   我刚刚重建了最新版本的RestSharp（版本105.1.0）并启用了此选项。 使用以下版本的课程：

    [DataContract] public class CallRequest { [DataMember(Name = "from")] public string From { get; set; } [DataMember(Name = "to")] public string To { get; set; } [DataMember(Name = "answer_url")] public string AnswerUrl { get; set; } } 

   我能够生成以下JSON：

     var request = new CallRequest { AnswerUrl = "AnswerUrl", From = "from", To = "to" }; var json = SimpleJson.SerializeObject(request); Debug.WriteLine(json); // Prints {"from":"from","to":"to","answer_url":"AnswerUrl"} 

   但是，我不确定这个选项是如何彻底测试的，因为它是默认编译出来的。

2. 使用不同的序列化程序（如支持属性重命名的Json.NET）手动序列化和反序列化。 要执行此操作，请参阅RestSharp – 使用Json.net序列化程序 （ 在此存档。）