获取没有标题的窗口的句柄..（C＃）

我们如何获得没有标题的窗口的句柄？ 有没有办法枚举桌面上的所有窗口并过滤没有标题的窗口（在我的情况下，只有一个）并获取它的句柄..或通过指定其他属性，如一个窗口，特定的按钮或列表框等…

Answer 1

这应该这样做：

... using System.Runtime.InteropServices; using System.Diagnostics; ... public class foo() { ... [DllImport ("user32")] internal static extern int GetWindowText (int hWnd, String text, int nMaxCount); [DllImport ("user32.dll")] public static extern int GetWindowTextLength (int hWnd); [DllImport ("user32.dll")] public static extern int FindWindow (String text, String class_name); [DllImport ("user32.dll")] public static extern int FindWindowEx (int parent, int start, String class_name); [DllImport ("user32.dll")] public static extern int GetWindow (int parent, uint cmd); public List FindTitlelessWindows() { List titleless = new List (); Process [] procs = Process.GetProcesses (); IntPtr hWnd; foreach (Process proc in procs) { hWnd = proc.MainWindowHandle; if (hWnd != IntPtr.Zero) { TraverseHierarchy (hWnd.ToInt32 (), 0, titleless); } } foreach (int i in titleless) { System.Console.WriteLine (i); } return titleless; } public void TraverseHierarchy (int parent, int child, List titleless) { String text = ""; GetWindowText (parent, text, GetWindowTextLength (parent)); if (String.IsNullOrEmpty (text)) { titleless.Add (parent); } TraverseChildern (parent, titleless); TraversePeers (parent, child, titleless); } public void TraverseChildern(int handle, List titleless) { // First traverse child windows const uint GW_CHILD = 0x05; int child = GetWindow (handle, GW_CHILD); if (0 != child) { TraverseHierarchy (child, 0, titleless); } } public void TraversePeers(int parent, int start, List titleless) { // Next traverse peers int peer = FindWindowEx(parent, start, ""); if (0 != peer) { TraverseHierarchy (parent, peer, titleless); } } } 

Answer 2

看看EnumChildWindows函数。

我认为，如果您将主窗口（即桌面）的指针传递给此函数，您将能够获得所有窗口及其子窗口的列表。

与FindWindow结合使用，一旦找到预期的子控件，就可以获得所需窗口的句柄。

Answer 3

像这样的东西应该工作， 而不是测试

 [DllImport("user32", CharSet = CharSet.Auto, SetLastError = true)] internal static extern int GetWindowText(IntPtr hWnd, [Out, MarshalAs(UnmanagedType.LPTStr)] StringBuilder lpString, int nMaxCount); [DllImport("user32.dll", SetLastError = true, CharSet = CharSet.Auto)] public static extern int GetWindowTextLength(IntPtr hWnd); .... Process[] procs = Process.GetProcesses(); IntPtr hWnd; foreach(Process proc in procs) { hWnd = proc.MainWindowHandle; if (hWnd != IntPtr.Zero) { int length = GetWindowTextLength(hWnd); StringBuilder sb = new StringBuilder(length + 1); GetWindowText(hWnd, sb, length); if (String.IsNullOrEmpty(sb.ToString()) { // we have a window with no title! } } } 

Answer 4

http://msdn.microsoft.com/en-us/library/ms633558(VS.85).aspx

WindowFromPoint返回一个句柄，如果光标下没有窗口，则返回null。 可以使用，还是你试图自动化这个过程？

Answer 5

在这里，您可以找到一个库来处理托管代码中的Windows API内容。
下载dll并在您的项目中引用它，从那里可以很容易地获得您想要的任何窗口的任何信息;

  void ForAllSystemWindows() { foreach (SystemWindow window in SystemWindow.AllToplevelWindows) { if (window.Title == string.Empty) { //Found window without title //Get window handle IntPtr windowhandle = window.HWnd; //Do other stuff .. } } }