我如何以编程方式从数据库表中“插入”数据脚本文件？

是否有一个优雅的面向对象的框架？

Answer 1

下面是我编写的一些代码，用于为数据库中的每个表生成“插入”存储过程。 它还处理为具有标识列的表返回新id。 它使用SQL SMO。 其中一些对我的项目有点具体，所以如果您有任何问题，请告诉我。

void InsertScripts(Database db) { var tables = db.Tables.ToIEnumerable(); //this is an extension method to convert Database.Tables into an IEnumerable { foreach (var t in tables) { var sb = new StringBuilder(); var sp = new StoredProcedure(db, "gen_insert_" + t.Name); sp.AnsiNullsStatus = false; sp.QuotedIdentifierStatus = false; sp.TextMode = false; var columns = t.Columns.ToIEnumerable().Where(c => !c.Identity && !c.IsReadOnly()).ToList(); foreach (var c in columns) { var p = new StoredProcedureParameter(sp, "@" + t.Name + "_" + c.Name, c.DataType); p.IsCursorParameter = false; if(c.Default != null && c.Default.Length > 0) p.DefaultValue = c.Default; if (c.Nullable) p.DefaultValue = "NULL"; sp.Parameters.Add(p); } var cols = string.Join(",", columns.Select(c => c.Name).ToArray()); var vals = string.Join(",", columns.Select(c => "@" + t.Name + "_" + c.Name).ToArray()); var sql = string.Format("insert into {0} ({1}) values ({2});", t.Name, cols, vals); sb.AppendLine(sql); if (t.Columns.ToIEnumerable().Any(c => c.Identity)) { var declaration = "declare @newid int;\r\n"; var ret = "select @newid = scope_identity();\r\nselect @newid;\r\nreturn @newid"; sb.Insert(0, declaration); sb.AppendLine(ret); } sp.TextBody = sb.ToString(); if(cols.Length > 0 && sp.Parent.StoredProcedures[sp.Name] == null) sp.Create(); } } } public static class Utils //Extension methods... { public static IEnumerable ToIEnumerable(this TableCollection tables) { var list = new List(); foreach (Table t in tables) list.Add(t); return list; } public static IEnumerable ToIEnumerable(this ViewCollection views) { var list = new List(); foreach (View v in views) list.Add(v); return list; } public static IEnumerable ToIEnumerable(this ColumnCollection columns) { var list = new List(); foreach (Column c in columns) list.Add(c); return list; } public static IEnumerable ToIEnumerable(this ForeignKeyCollection columns) { var list = new List(); foreach (ForeignKey c in columns) list.Add(c); return list; } public static IEnumerable ToIEnumerable(this ForeignKeyColumnCollection columns) { var list = new List(); foreach (ForeignKeyColumn c in columns) list.Add(c.Name); return list; } } 

Answer 2

听起来你想要一个ORM，或者你真的想要插入文本而不是插入？

您应该看看Linq To SQL。

Answer 3

我刚写了一个快速的脏数据导出脚本（很长一段时间你无法通过SSMS访问数据库）。 无论如何，这可能有助于未来的人：

 var result = new StringBuilder(); using (var con = new SqlConnection(ConfigurationManager.ConnectionStrings["MyConnectionString"].ConnectionString)) { con.Open(); using (var cmd = con.CreateCommand()) { cmd.CommandText = @" DECLARE @name VARCHAR(255) DECLARE iterator CURSOR FOR SELECT name FROM sys.tables WHERE type='U' OPEN iterator FETCH NEXT FROM iterator INTO @name WHILE @@FETCH_STATUS = 0 BEGIN SELECT @name name EXEC ('SELECT * FROM ' + @name) FETCH NEXT FROM iterator INTO @name END CLOSE iterator DEALLOCATE iterator "; using (var reader = cmd.ExecuteReader()) { do { // get table name reader.Read(); string tableName = reader[0].ToString(); // get contents reader.NextResult(); result .Append("SET IDENTITY_INSERT ") .Append(tableName) .Append(" ON\r\n"); while (reader.Read()) { result .Append("INSERT ") .Append(tableName) .Append(" ("); for (var x = 0; x < reader.FieldCount; x++) result .Append(x == 0 ? string.Empty : ",") .Append("[" + reader.GetName(x) + "]"); result .Append(" ) VALUES ("); for (var x = 0; x < reader.FieldCount; x++) result .Append(x == 0 ? string.Empty : ",") .Append("'" + reader[x].ToString() + "'"); result .Append(")\r\n"); } result .Append("SET IDENTITY_INSERT ") .Append(tableName) .Append(" OFF\r\n"); } while (reader.NextResult()); } } } Response.Write(result);