如何从URL中获取数据并将其保存到C＃.NET中的二进制文件中，而不会出现编码问题？

在C＃.NET中，我想从URL获取数据并将其保存为二进制文件。

使用HttpWebRequest / Streamreader读取字符串并使用StreamWriter保存可以正常使用ASCII，但非ASCII字符会受到损坏，因为系统认为它必须担心编码，编码为Unicode或来自或等等。

从URL获取数据并将其保存到文件（二进制文件）的最简单方法是什么？

// This code works, but for ASCII only String url = "url..."; HttpWebRequest request = (HttpWebRequest) WebRequest.Create(url); // execute the request HttpWebResponse response = (HttpWebResponse) request.GetResponse(); // we will read data via the response stream Stream ReceiveStream = response.GetResponseStream(); StreamReader readStream = new StreamReader( ReceiveStream ); string contents = readStream.ReadToEnd(); string filename = @"..."; // create a writer and open the file TextWriter tw = new StreamWriter(filename); tw.Write(contents.Substring(5)); tw.Close(); 

Answer 1

极简主义回答：

 using (WebClient client = new WebClient()) { client.DownloadFile(url, filePath); } 

或者在PowerShell中（在匿名编辑中建议）：

 [System.Net.WebClient]::WebClient $client = New-Object System.Net.WebClient $client.DownloadFile(URL, Filename) 

Answer 2

只是不要使用任何StreamReader或TextWriter。 使用原始FileStream保存到文件中。

 String url = ...; HttpWebRequest request = (HttpWebRequest) WebRequest.Create(url); // execute the request HttpWebResponse response = (HttpWebResponse) request.GetResponse(); // we will read data via the response stream Stream ReceiveStream = response.GetResponseStream(); string filename = ...; byte[] buffer = new byte[1024]; FileStream outFile = new FileStream(filename, FileMode.Create); int bytesRead; while((bytesRead = ReceiveStream.Read(buffer, 0, buffer.Length)) != 0) outFile.Write(buffer, 0, bytesRead); // Or using statement instead outFile.Close() 

Answer 3

这是我用的：

 sUrl = "http://your.com/xml.file.xml"; rssReader = new XmlTextReader(sUrl.ToString()); rssDoc = new XmlDocument(); WebRequest wrGETURL; wrGETURL = WebRequest.Create(sUrl); Stream objStream; objStream = wrGETURL.GetResponse().GetResponseStream(); StreamReader objReader = new StreamReader(objStream, Encoding.UTF8); WebResponse wr = wrGETURL.GetResponse(); Stream receiveStream = wr.GetResponseStream(); StreamReader reader = new StreamReader(receiveStream, Encoding.UTF8); string content = reader.ReadToEnd(); XmlDocument content2 = new XmlDocument(); content2.LoadXml(content); content2.Save("direct.xml");