OpenXML替换所有文档中的文本

我有下面的代码。 我想用“NewText”替换文本“Text1”，这是有效的。 但是当我将文本“Text1”放在一个不再适用于表格中的“Text1”的表格中时。

我想在所有文件中进行替换。

using (WordprocessingDocument doc = WordprocessingDocument.Open(String.Format("c:\\temp\\filename.docx"), true)) { var body = doc.MainDocumentPart.Document.Body; foreach (var para in body.Elements()) { foreach (var run in para.Elements()) { foreach (var text in run.Elements()) { if (text.Text.Contains("##Text1##")) text.Text = text.Text.Replace("##Text1##", "NewText"); } } } } 

Answer 1

您的代码不起作用，因为table元素（ w:tbl ）不包含在段落元素（ w:p ）中。 有关更多信息，请参阅以下MSDN文章。

Text类（序列化为w:t ）通常表示word文档中Run元素中的文字文本。 因此，如果文本元素（ w:t ）包含您的标记，您可以简单地搜索所有w:t元素（ Text类）并替换您的标记：

 using (WordprocessingDocument doc = WordprocessingDocument.Open("yourdoc.docx", true)) { var body = doc.MainDocumentPart.Document.Body; foreach (var text in body.Descendants()) { if (text.Text.Contains("##Text1##")) { text.Text = text.Text.Replace("##Text1##", "NewText"); } } } 

Answer 2

在各个地方借用其他一些答案，并且必须克服四个主要障碍：

1. 删除无法从Word中读取的替换字符串中的任何高级Unicode字符（来自错误的用户输入）
2. 能够在段落中的多个运行或文本元素中搜索查找结果（Word通常会将单个句子拆分为多个文本运行）
3. 能够在替换文本中包含换行符，以便将多行文本插入到文档中。
4. 能够传入任何节点作为搜索的起点，以便将搜索限制在文档的该部分（例如正文，页眉，页脚，特定表，表格行或表格单元格）。

我确信书签，复杂嵌套等高级场景需要对此进行更多修改，但它适用于我到目前为止遇到的基本单词文档的类型，并且比完全忽略运行或使用RegEx在整个文件上无法定位特定的TableCell或Document部分（针对高级方案）。

用法示例：

  var body = document.MainDocumentPart.Document.Body; ReplaceText(body, replace, with); 

代码：

 using System; using System.Collections.Generic; using System.Linq; using DocumentFormat.OpenXml; using DocumentFormat.OpenXml.Packaging; using DocumentFormat.OpenXml.Wordprocessing; namespace My.Web.Api.OpenXml { public static class WordTools { /// 
 /// Find/replace within the specified paragraph. /// 
 ///  ///  ///  public static void ReplaceText(Paragraph paragraph, string find, string replaceWith) { var texts = paragraph.Descendants(); for (int t = 0; t < texts.Count(); t++) { // figure out which Text element within the paragraph contains the starting point of the search string Text txt = texts.ElementAt(t); for (int c = 0; c < txt.Text.Length; c++) { var match = IsMatch(texts, t, c, find); if (match != null) { // now replace the text string[] lines = replaceWith.Replace(Environment.NewLine, "\r").Split('\n', '\r'); // handle any lone n/r returns, plus newline. int skip = lines[lines.Length - 1].Length - 1; // will jump to end of the replacement text, it has been processed. if (c > 0) lines[0] = txt.Text.Substring(0, c) + lines[0]; // has a prefix if (match.EndCharIndex + 1 < texts.ElementAt(match.EndElementIndex).Text.Length) lines[lines.Length - 1] = lines[lines.Length - 1] + texts.ElementAt(match.EndElementIndex).Text.Substring(match.EndCharIndex + 1); txt.Space = new EnumValue(SpaceProcessingModeValues.Preserve); // in case your value starts/ends with whitespace txt.Text = lines[0]; // remove any extra texts. for (int i = t + 1; i <= match.EndElementIndex; i++) { texts.ElementAt(i).Text = string.Empty; // clear the text } // if 'with' contained line breaks we need to add breaks back... if (lines.Count() > 1) { OpenXmlElement currEl = txt; Break br; // append more lines var run = txt.Parent as Run; for (int i = 1; i < lines.Count(); i++) { br = new Break(); run.InsertAfter(br, currEl); currEl = br; txt = new Text(lines[i]); run.InsertAfter(txt, currEl); t++; // skip to this next text element currEl = txt; } c = skip; // new line } else { // continue to process same line c += skip; } } } } } /// 
 /// Determine if the texts (starting at element t, char c) exactly contain the find text /// 
 ///  ///  ///  ///  /// null or the result info static Match IsMatch(IEnumerable texts, int t, int c, string find) { int ix = 0; for (int i = t; i < texts.Count(); i++) { for (int j = c; j < texts.ElementAt(i).Text.Length; j++) { if (find[ix] != texts.ElementAt(i).Text[j]) { return null; // element mismatch } ix++; // match; go to next character if (ix == find.Length) return new Match() { EndElementIndex = i, EndCharIndex = j }; // full match with no issues } c = 0; // reset char index for next text element } return null; // ran out of text, not a string match } /// 
 /// Defines a match result /// 
 class Match { /// 
 /// Last matching element index containing part of the search text /// 
 public int EndElementIndex { get; set; } /// 
 /// Last matching char index of the search text in last matching element /// 
 public int EndCharIndex { get; set; } } } // class } // namespace public static class OpenXmlTools { // filters control characters but allows only properly-formed surrogate sequences private static Regex _invalidXMLChars = new Regex( @"(? /// removes any unusual unicode characters that can't be encoded into XML which give exception on save ///  public static string RemoveInvalidXMLChars(string text) { if (string.IsNullOrEmpty(text)) return ""; return _invalidXMLChars.Replace(text, ""); } } 

Answer 3

也许这个解决方案更容易

 using (WordprocessingDocument wordDoc = WordprocessingDocument.Open(document, true)) { string docText = null; //1. Copy all the file into a string using (StreamReader sr = new StreamReader(wordDoc.MainDocumentPart.GetStream())) docText = sr.ReadToEnd(); //2. Use regular expression to replace all text Regex regexText = new Regex(find); docText = regexText.Replace(docText, replace); //3. Write the changed string into the file again using (StreamWriter sw = new StreamWriter(wordDoc.MainDocumentPart.GetStream(FileMode.Create))) sw.Write(docText);