LINQ中SQL Server版本的Oracle CONNECT BY显示层次结构

我已经在SQL Server 2008中成功模拟了一个Oracle CONNECT BY语句，在这里和这里按照这两个前面的答案并调整以获得我需要的结果。 但是我如何在LINQ中执行此操作？

这是我使用虚拟数据库做的一个例子：

CREATE TABLE Employee( EmployeeID INT IDENTITY(1,1) PRIMARY KEY, Department INT NOT NULL, EmployeeName VARCHAR(40) NOT NULL, PeckingOrder INT NOT NULL, HigherDepartment INT NULL) INSERT INTO Employee (Department,EmployeeName,PeckingOrder,HigherDepartment) VALUES (1,'Bart',1,NULL),(2,'Homer',1,1),(2,'Marge',2,NULL), (3,'Lisa',1,2),(3,'Maggie',2,2),(3,'Santas Helper',3,1) EmployeeID Department EmployeeName PeckingOrder HigherDepartment 1 1 Bart 1 NULL 2 2 Homer 1 1 3 2 Marge 2 NULL 4 3 Lisa 1 2 5 3 Maggie 2 2 6 3 Santas Helper 3 1 

这是用于返回heirachy的SQL：

 WITH n(level, PeckingOrder, Department, EmployeeName, HigherDepartment) AS (SELECT 1, PeckingOrder, Department, EmployeeName, HigherDepartment FROM Test.dbo.Employee WHERE Department = 3 UNION ALL SELECT n.level + 1, nplus1.PeckingOrder, nplus1.Department, nplus1.EmployeeName, nplus1.HigherDepartment FROM Test.dbo.Employee as nplus1 JOIN n ON n.HigherDepartment = nplus1.Department) SELECT MAX(level) AS level, PeckingOrder, Department, EmployeeName, HigherDepartment FROM n GROUP BY PeckingOrder, Department, EmployeeName, HigherDepartment ORDER BY MAX(level) DESC, PeckingOrder ASC level PeckingOrder Department EmployeeName HigherDepartment 3 1 1 Bart NULL 2 1 2 Homer 1 2 2 2 Marge NULL 1 1 3 Lisa 2 1 2 3 Maggie 2 1 3 3 Santas Helper 1 

Answer 1

您可以使用ExecuteQuery ：

 class YourRow { public int level {get; set;} public int PeckingOrder {get; set;} ... } using (var db = new LinqDataContext()) { var list = db.ExecuteQuery( @" WITH n(level, PeckingOrder, Department, EmployeeName, HigherDepartment) AS (SELECT 1, PeckingOrder, Department, EmployeeName, HigherDepartment ... "; } 

或者更好，创建一个包含查询的视图，并使用LINQ从视图中读取。