SQL如何在两个日期之间的一小时内对事件求和并将其显示在一行中

我正在用C＃和SQL server 2005开发一个报告，我只需要显示我们每小时收到多少命中。 桌子很大。 输出应如下所示：

行＃| 日期| 时间| 命中数
 -----------------------------
 1 |  07/05/2012 |  8:00 |  3
 2 |  07/05/2012 |  9:00 |  4
 3 |  07/05/2012 |  10:00 |  0
 4 |  07/05/2012 |  11:00 | 五

我的表看起来像这样：

 “HitTime”：

 07/05/2012 08:02:24
 07/05/2012 08:12:21
 07/05/2012 08:23:00
 07/05/2012 09:01:00
 07/05/2012 09:08:14
 07/05/2012 09:12:31
 07/05/2012 09:22:27

..etc正如你在HitTime字段中看到的那样我只有日期和时间，我需要在同一天显示，例如从8:00到8:59，我得到了多少点击，它应该是整天，从那天的第一秒开始直到第二天结束。

Answer 1

DECLARE @current_date DATETIME SET @current_date = '2012-05-07'; WITH hours (hr) AS ( SELECT 0 UNION ALL SELECT hr + 1 FROM hours WHERE hr < 23 ) SELECT ROW_NUMBER() OVER (ORDER BY hr) AS rn, @current_date AS [date], CONVERT(VARCHAR(5), DATEADD(hour, h.hr, @current_date), 108) AS [time], COUNT(hs.hittime) AS hitcount FROM hours h LEFT JOIN hits hs ON hs.hittime >= DATEADD(hour, h.hr, @current_date) AND hs.hittime < DATEADD(hour, h.hr + 1, @current_date) GROUP BY hr 

Answer 2

这个怎么样？

 ;WITH aggregation(hit_date, hit_time) AS ( SELECT DATEADD(dd, DATEDIFF(dd, 0, hittime), 0) , DATEPART(hour, hittime) FROM test ) SELECT ROW_NUMBER() OVER (ORDER BY hit_date, hit_time) AS rn , CONVERT(VARCHAR,hit_date,101) as [date] , CAST(hit_time AS VARCHAR) + ':00' as [time] , COUNT(*) as hit_count FROM aggregation GROUP BY hit_date , hit_time 

Answer 3

 WITH hit_count AS( select CONVERT(VARCHAR,hit_time,101)as [date], substring(convert(varchar,hit_time,108), 0, 4)+'00' as [time] from hit ) select date,[time], count(*) as hit from hit_count group by [time],[date] 

如果你想要AM / PM那么：

 WITH hit_count AS( select CONVERT(VARCHAR,hit_time,101)as [date], (substring(convert(varchar,hit_time,100), 12, 4)+'00'+substring(convert(varchar,hit_time,100),18,2)) as [time] from hit ) select date,[time], count(*) as hit from hit_count group by [time],[date] GO