如何使用具有相同键的两个不同词典的值来构建新词典
假设我们有两个带有以下键对值的字典：
- 字典1：[{1，abc} {2，cde} {3，efg}]
- 字典2：[{1,123} {2,234} {3,345}]
-
我想创建一个字典如下：字典3：[{abc，123} {cde，234} {efg，345}]
fieldValues = new List<List>(); docFieldKey = new List<List>(); docFieldValueDict = new Dictionary<string, List>(); docKeyDict = new Dictionary<string, List>(); iterateDocKeyDict = new List(); iterateDocFldValueDict = new List(); //To read row wise and store key and all values for (limit = 0; limit < docNames.Count; limit++) { for (row = 0; row < excelData.Count; row++) { if (excelData[row] == docNames[limit]) { for (colLimit = row + 1; colLimit < fieldNames.Count; colLimit++) { flag = true; fieldValues.Add(new List()); fieldValues[limit].Add(excelData[colLimit]); } if (flag == true) { docFieldValueDict.Add(docNames[limit], fieldValues[limit]); } } } } //To add concatenated key for each docName for (limit = 0; limit < docNames.Count; limit++) { for (colLimit = 0; colLimit < concatKey.Count; colLimit++) { if (concatKey[colLimit].Contains(docNames[limit])) { for (col = colLimit; col < fieldNames.Count - 1; col++) { flag = true; docFieldKey.Add(new List()); docFieldKey[limit].Add(concatKey[col]); } if (flag == true) { docKeyDict.Add(docNames[limit], docFieldKey[limit]); } } } } //to merge the key and the value from both dictionaries for (limit = 0; limit <docKeyDict.Count; limit++) { var docKeyDictCompare = docKeyDict.ElementAt(limit); var docFldValueDictCompare = docFieldValueDict.ElementAt(limit); iterateDocKeyDict = docKeyDictCompare.Value; iterateDocFldValueDict = docFldValueDictCompare.Value; if (docKeyDictCompare.Key == docFldValueDictCompare.Key) { for (col = 0; col < fieldNames.Count - 1; col++) { if ((iterateDocKeyDict.ElementAt(col)!=string.Empty) && (iterateDocFldValueDict.ElementAt(col)!=string.Empty)) { flag = true; } } if (flag == true) { keyValuePairDict.Add(iterateDocKeyDict.ElementAt(col), iterateDocFldValueDict.ElementAt(col)); } } }
我尝试了上面的但是我得到的索引超出了范围exception
if ((iterateDocKeyDict.ElementAt(col)!=string.Empty) &&(iterateDocFldValueDict.ElementAt(col)!=string.Empty)) 在控制台中显示错误消息
只是看你的样本词典我会建议：
var dic1 = /* [ {1,abc} {2,cde} {3,efg} ] */; var dic2 = /* [ {1,123} {2,234} {3,345} ] */; var dic3 = dic1.ToDictionary(x => x.Value, x => dic2[x.Key]);
但是看一下相当长的代码示例，我不确定它是否足够。
试试这样：
var dictionaryC = dictionaryA.ToDictionary(dicA => dicA.Value, dicA => dictionaryB[dicA.Key]);