计算年，月，周和日

在我的应用程序中，用户输入两个日期。 计划的开始日期和计划的结束日期。 我们必须采用这些日期，并根据差异填充4个字段。

所以，让我们说他选择2010年1月1日作为开始，2011年3月2日作为结束，我们需要最终得到：

年：1个月：2周：0天1

意思是总持续时间为1年，2个月和1天。

有这样做的标准方法吗？ 或者我是否需要编写一个具有许多非常棘手的逻辑的方法来解决它？ 我希望我很幸运，并且会有一个date-diff类型.Net类可用。

Answer 1

我认为TimeSpan正是您所寻找的，但它不需要数年或数月，因为它们的长度各不相同。

以下示例来自上述链接;

// Define two dates. DateTime date1 = new DateTime(2010, 1, 1, 8, 0, 15); DateTime date2 = new DateTime(2010, 8, 18, 13, 30, 30); // Calculate the interval between the two dates. TimeSpan interval = date2 - date1; Console.WriteLine("{0} - {1} = {2}", date2, date1, interval.ToString()); // Display individual properties of the resulting TimeSpan object. Console.WriteLine(" {0,-35} {1,20}", "Value of Days Component:", interval.Days); Console.WriteLine(" {0,-35} {1,20}", "Total Number of Days:", interval.TotalDays); Console.WriteLine(" {0,-35} {1,20}", "Value of Hours Component:", interval.Hours); Console.WriteLine(" {0,-35} {1,20}", "Total Number of Hours:", interval.TotalHours); Console.WriteLine(" {0,-35} {1,20}", "Value of Minutes Component:", interval.Minutes); Console.WriteLine(" {0,-35} {1,20}", "Total Number of Minutes:", interval.TotalMinutes); Console.WriteLine(" {0,-35} {1,20:N0}", "Value of Seconds Component:", interval.Seconds); Console.WriteLine(" {0,-35} {1,20:N0}", "Total Number of Seconds:", interval.TotalSeconds); Console.WriteLine(" {0,-35} {1,20:N0}", "Value of Milliseconds Component:", interval.Milliseconds); Console.WriteLine(" {0,-35} {1,20:N0}", "Total Number of Milliseconds:", interval.TotalMilliseconds); Console.WriteLine(" {0,-35} {1,20:N0}", "Ticks:", interval.Ticks); // the example displays the following output: // 8/18/2010 1:30:30 PM - 1/1/2010 8:00:15 AM = 229.05:30:15 // Value of Days Component: 229 // Total Number of Days: 229.229340277778 // Value of Hours Component: 5 // Total Number of Hours: 5501.50416666667 // Value of Minutes Component: 30 // Total Number of Minutes: 330090.25 // Value of Seconds Component: 15 // Total Number of Seconds: 19,805,415 // Value of Milliseconds Component: 0 // Total Number of Milliseconds: 19,805,415,000 // Ticks: 198,054,150,000,000 

Answer 2

这是一个完整的方法，不包括数周，但可以相对简单地添加。 这是一个有点复杂的问题（在stackoverflow上以多种方式提出问题，并且在很多方面都得到了很好的回答），但是可以回答这个问题。 TimeSpan对象为我们提供了我们需要的部分内容，但只能在几天内完成。 我已经针对这种方法编写了大量测试，如果你发现了漏洞，请发表评论。

这将做的是比较2个日期，得到年，月，日，小时和分钟。 （例如某些事件发生在1年，6个月，3天，4小时和7分钟前）

因为这个问题已被提出并试图多次回答，我不确定这会不会被注意到，但如果是这样，它应该提供价值。

  public static void TimeSpanToDateParts(DateTime d1, DateTime d2, out int years, out int months, out int days, out int hours, out int minutes) { if (d1 < d2) { var d3 = d2; d2 = d1; d1 = d3; } var span = d1 - d2; months = 12 * (d1.Year - d2.Year) + (d1.Month - d2.Month); //month may need to be decremented because the above calculates the ceiling of the months, not the floor. //to do so we increase d2 by the same number of months and compare. //(500ms fudge factor because datetimes are not precise enough to compare exactly) if (d1.CompareTo(d2.AddMonths(months).AddMilliseconds(-500)) <= 0) { --months; } years = months / 12; months -= years * 12; if (months == 0 && years == 0) { days = span.Days; } else { var md1 = new DateTime(d1.Year, d1.Month, d1.Day); // Fixed to use d2.Day instead of d1.Day var md2 = new DateTime(d2.Year, d2.Month, d2.Day); var mDays = (int) (md1 - md2).TotalDays; if (mDays > span.Days) { mDays = (int)(md1.AddMonths(-1) - md2).TotalDays; } days = span.Days - mDays; } hours = span.Hours; minutes = span.Minutes; } 

Answer 3

您可以使用此免费库的DateDiff类：

 // ---------------------------------------------------------------------- public void DateDiffSample() { DateTime date1 = new DateTime( 2009, 11, 8, 7, 13, 59 ); Console.WriteLine( "Date1: {0}", date1 ); // > Date1: 08.11.2009 07:13:59 DateTime date2 = new DateTime( 2011, 3, 20, 19, 55, 28 ); Console.WriteLine( "Date2: {0}", date2 ); // > Date2: 20.03.2011 19:55:28 DateDiff dateDiff = new DateDiff( date1, date2 ); // differences Console.WriteLine( "DateDiff.Years: {0}", dateDiff.Years ); // > DateDiff.Years: 1 Console.WriteLine( "DateDiff.Quarters: {0}", dateDiff.Quarters ); // > DateDiff.Quarters: 5 Console.WriteLine( "DateDiff.Months: {0}", dateDiff.Months ); // > DateDiff.Months: 16 Console.WriteLine( "DateDiff.Weeks: {0}", dateDiff.Weeks ); // > DateDiff.Weeks: 70 Console.WriteLine( "DateDiff.Days: {0}", dateDiff.Days ); // > DateDiff.Days: 497 Console.WriteLine( "DateDiff.Weekdays: {0}", dateDiff.Weekdays ); // > DateDiff.Weekdays: 71 Console.WriteLine( "DateDiff.Hours: {0}", dateDiff.Hours ); // > DateDiff.Hours: 11940 Console.WriteLine( "DateDiff.Minutes: {0}", dateDiff.Minutes ); // > DateDiff.Minutes: 716441 Console.WriteLine( "DateDiff.Seconds: {0}", dateDiff.Seconds ); // > DateDiff.Seconds: 42986489 // elapsed Console.WriteLine( "DateDiff.ElapsedYears: {0}", dateDiff.ElapsedYears ); // > DateDiff.ElapsedYears: 1 Console.WriteLine( "DateDiff.ElapsedMonths: {0}", dateDiff.ElapsedMonths ); // > DateDiff.ElapsedMonths: 4 Console.WriteLine( "DateDiff.ElapsedDays: {0}", dateDiff.ElapsedDays ); // > DateDiff.ElapsedDays: 12 Console.WriteLine( "DateDiff.ElapsedHours: {0}", dateDiff.ElapsedHours ); // > DateDiff.ElapsedHours: 12 Console.WriteLine( "DateDiff.ElapsedMinutes: {0}", dateDiff.ElapsedMinutes ); // > DateDiff.ElapsedMinutes: 41 Console.WriteLine( "DateDiff.ElapsedSeconds: {0}", dateDiff.ElapsedSeconds ); // > DateDiff.ElapsedSeconds: 29 } // DateDiffSample 

Answer 4

调查C＃ TimeSpan结构。 它没有几个月或几年，但确实需要几天。 这使事情变得更容易。

Answer 5

  public partial class Age1 : System.Web.UI.Page { private int Years; private int Months; private int Days; DateTime Cday; DateTime Bday; protected void Page_Load(object sender, EventArgs e) { txtCurrentDate.Enabled = false; txtCurrentDate.Text = DateTime.Now.ToString("g"); Cday = Convert.ToDateTime(txtCurrentDate.Text); } protected void Button1_Click(object sender, EventArgs e) { Bday = Convert.ToDateTime(txtBirthdate.Text); AgeCaluclation(Bday, Cday); txtBirthdate.Text = ""; txtCurrentDate.Text = ""; lblAge.Text = this.Years+" Years "+this.Months+" Months " +this.Days+ "Days"; } private Age1 AgeCaluclation(DateTime Bday, DateTime Cday) { if ((Cday.Year - Bday.Year) > 0 || (((Cday.Year - Bday.Year) == 0) && ((Bday.Month < Cday.Month) || ((Bday.Month == Cday.Month) && (Bday.Day <= Cday.Day))))) { int DaysInBdayMonth = DateTime.DaysInMonth(Bday.Year, Bday.Month); int DaysRemain = Cday.Day + (DaysInBdayMonth - Bday.Day); if(Cday.Month > Bday.Month) { this.Years = Cday.Year - Bday.Year; this.Months = Cday.Month - (Bday.Month + 1) + Math.Abs(DaysRemain / DaysInBdayMonth); this.Days = (DaysRemain % DaysInBdayMonth + DaysInBdayMonth) % DaysInBdayMonth; } else if (Cday.Month == Bday.Month) { if (Cday.Day >= Bday.Day) { this.Years = Cday.Year - Bday.Year; this.Months = 0; this.Days = Cday.Day - Bday.Day; } else { this.Years = (Cday.Year - 1) - Bday.Year; this.Months = 11; this.Days = DateTime.DaysInMonth(Bday.Year, Bday.Month) - (Bday.Day - Cday.Day); } } else { this.Years = (Cday.Year - 1) - Bday.Year; this.Months = Cday.Month + (11 - Bday.Month) + Math.Abs(DaysRemain / DaysInBdayMonth); this.Days = (DaysRemain % DaysInBdayMonth + DaysInBdayMonth) % DaysInBdayMonth; } } else { throw new ArgumentException("Birthday date must be earlier than current date"); } return this; } } 

Answer 6

我也需要这个，但就我而言，没有周数（所以只有几年，几个月和几天）。 鉴于此，这就是我所做的：

 DateTime startDate = DateTime.ParseExact (start, "dd/MM/yyyy",CultureInfo.InvariantCulture); DateTime endDate = DateTime.ParseExact (end, "dd/MM/yyyy",CultureInfo.InvariantCulture); int days=0; int months = 0; int years = 0; //calculate days if (endDate.Day >= startDate.Day) { days = endDate.Day - startDate.Day; } else { var tempDate = endDate.AddMonths (-1); int daysInMonth = DateTime.DaysInMonth (tempDate.Year, tempDate.Month); days = daysInMonth - (startDate.Day - endDate.Day); months--; } //calculate months if (endDate.Month >= startDate.Month) { months+=endDate.Month - startDate.Month; } else { months+= 12 - (startDate.Month - endDate.Month); years--; } //calculate years years+=endDate.Year - startDate.Year; Debug.WriteLine (string.Format("{0} years, {1} months, {2} days",years,months,days)); 

如果您想更动态地显示它，您还可以使用以下代码：

 //build the string var result = ""; if (years!=0){ result = years == 1 ? years + " year" : years + " years"; } if (months != 0) { if (result != "") { result += ", "; } result += months == 1 ? months + " month" : months + " months"; } if (days != 0) { if (result != "") { result += ", "; } result += days == 1 ? days + " day" : days + " days"; } Debug.WriteLine (result); 

Answer 7

我创建了这个用于返回两个日期之间的年，月和日的差异。

 public static Dictionary TimeSpanToDateParts(DateTime fromDate,DateTime toDate) { int years; int months; int days; Dictionary dateParts = new Dictionary(); if (toDate < fromDate) { return TimeSpanToDateParts(toDate,fromDate); } var span = toDate - fromDate; months = 12 * (toDate.Year - fromDate.Year) + (toDate.Month - fromDate.Month); if (toDate.CompareTo(fromDate.AddMonths(months).AddMilliseconds(-500)) <= 0) { --months; } years = months / 12; months -= years * 12; if (months == 0 && years == 0) { days = span.Days; } else { days = toDate.Day; if (fromDate.Day > toDate.Day) days = days + (DateTime.DaysInMonth(toDate.Year, toDate.Month - 1) - fromDate.Day); else days = days - fromDate.Day; } dateParts.Add("Years", years); dateParts.Add("Months", months); dateParts.Add("Days", days); return dateParts; }