XNA – 保持更长时间跳得更高

我正在为我的游戏寻找一种简单的方法，这样当你按住空格键时，你会跳得更高。 当你“点击”时，你不会跳到最大高度。 需要有一个最大值，但是，我不知道如何编程这个。

Anyhelp，非常感谢。 将给出反馈。 谢谢。

Answer 1

在你处理跳跃的更新function中，你可以让它跟踪角色离开地面的时间长度并让它的上升速度在一段时间后停止增加。

例如，以下内容应该有效

class Player { private const int gravity = 2; //force of gravity on the object private const int maxHeight = 5; //change as needed private const int msecsToMax = 1500; //change as needed private int yPos = 0; private int timeOffGround = 0; private yVel = 0; //other functions and stuff void update(GameTime gt) { //check if the player is on the ground and update as necessary if(isOnGround()) timeOffGround = 0; else timeOffGround += gt.ElapsedGameTime.TotalMilliseconds; //update the player's velocity yVel -= isOnGround() ? 0 : gravity; //no velocity when on the ground if(Keyboard.GetState().IsKeyDown(Keys.SPACE) && timeOffGround < msecsToMax)) yVel += (maxHeight / msecToMax); yPos += yVel; } } 

Answer 2

在跳跃的重音期间，Y速度被功率曲线完全覆盖。 在体面的过程中，重力接管了。 跳跃速度由jumpTime字段控制，该字段测量时间到当前跳跃的重音。

首先，你需要一些简单的全局变量，

 public bool isJumping; //Is the player in a jump? private bool wasJumping; //Did the player just exit a jump? private float jumpTime; //Time the player has been in a jump (Useful for adding a power curve or to max out on jump height) MaxJumpTime = .8f; //If you want to max out a jump, otherwise remove the relevant parts of the code JumpLaunchVelocity = -3000.0f; //How much velocity to "jump" with, this may depend on your speed of your player, so it will need some ajustment 

以下是完成大部分工作的function：

  private float DoJump(float velocityY, GameTime gameTime) { // If the player wants to jump if (isJumping) { // Begin or continue a jump if ((!wasJumping && IsOnGround) || jumpTime > 0.0f) { //Do things like animate, or play a sound here jumpTime += (float)gameTime.ElapsedGameTime.TotalSeconds; } // If we are in the ascent of the jump if (0.0f < jumpTime && jumpTime <= MaxJumpTime) { // Fully override the vertical velocity with a power curve that gives players more control over the top of the jump (If you dont want this you can remove the Math.Pow) velocityY = JumpLaunchVelocity * (1.0f - (float)Math.Pow(jumpTime / MaxJumpTime, JumpControlPower)); } else jumpTime = 0.0f; // Reached the apex of the jump } else { // Continues not jumping or cancels a jump in progress jumpTime = 0.0f; } wasJumping = isJumping; return velocityY; } 

在计算位置和内容时的更新中：

 velocity.Y = DoJump(velocity.Y, gameTime); 

如果您遇到任何问题，请查看Platformer入门套件 ！