从资源文件/内容获取流
这是从资源文件获取Stream的正确/唯一方法吗?
Uri uri = new Uri(fullPath); StorageFile storageFile = await Windows.Storage.StorageFile. GetFileFromApplicationUriAsync(uri); IRandomAccessStreamWithContentType randomAccessStream = await storageFile.OpenReadAsync(); IInputStream resourceStream = (IInputStream) randomAccessStream.GetInputStreamAt(0);
我的所有其他源(http和本地存储)都返回一个Stream对象,并且使用if-else代码使用其中一个或其他代码是很痛苦的。
我也尝试过创建一个MemoryStream,但我甚至找不到一个方法来获取字节…请帮助。
uint size = (uint)randomAccessStream.Size; IBuffer buffer = new Windows.Storage.Streams.Buffer(size); await randomAccessStream.ReadAsync(buffer, size, InputStreamOptions.None); Stream stream = new MemoryStream(buffer); // error takes byte[] not IBuffer
从资源中读取时的IInputStream.ReadAsync(): http : //msdn.microsoft.com/en-us/library/windows/apps/windows.storage.streams.iinputstream.readasync.aspx
而Stream.Read()和Stream.ReadAsync()看起来像这样:
http://msdn.microsoft.com/en-us/library/system.io.stream.read.aspx
和
http://msdn.microsoft.com/en-us/library/hh137813.aspx
谢谢
好的我找到了!
StorageFile storageFile = await Windows.Storage.StorageFile.GetFileFromApplicationUriAsync(uri); var randomAccessStream = await storageFile.OpenReadAsync(); Stream stream = randomAccessStream.AsStreamForRead();
你也可以少一行:
Stream stream = await storageFile.OpenStreamForReadAsync();