如何将文字拆分成文字?

如何将文字拆分成文字?

示例文字:

“哦,你无能为力,”猫说:“我们都疯了。 我生气了。 你疯了。’

该行中的文字是:

  1. 不能
  2. 救命
  3. 说过
  4. 我们
  5. 所有
  6. 这里
  7. 你是

在空格上拆分文本,然后修剪标点符号。

var text = "'Oh, you can't help that,' said the Cat: 'we're all mad here. I'm mad. You're mad.'"; var punctuation = text.Where(Char.IsPunctuation).Distinct().ToArray(); var words = text.Split().Select(x => x.Trim(punctuation)); 

完全同意例子。

首先,删除所有特殊的characeters:

 var fixedInput = Regex.Replace(input, "[^a-zA-Z0-9% ._]", string.Empty); // This regex doesn't support apostrophe so the extension method is better 

然后分开它:

 var splitted = fixedInput.Split(' '); 

对于更简单的C#解决方案来删除特殊字符(您可以轻松更改),请添加此扩展方法(我添加了对撇号的支持):

 public static string RemoveSpecialCharacters(this string str) { StringBuilder sb = new StringBuilder(); foreach (char c in str) { if ((c >= '0' && c <= '9') || (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || c == '\'') { sb.Append(c); } } return sb.ToString(); } 

然后像这样使用它:

 var words = input.RemoveSpecialCharacters().Split(' '); 

你会惊讶地发现这种扩展方法非常有效(肯定比正则表达式更高效)所以我建议你使用它;)

更新

我同意这是一种仅限英语的方法,但要使其兼容Unicode,您只需要替换:

 (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') 

附:

 char.IsLetter(c) 

哪个支持Unicode,。Net还为各种案例提供char.IsSymbolchar.IsLetterOrDigit

只是为@Adam Fridental的答案添加一个非常好的答案,你可以尝试这个正则表达式:

 var text = "'Oh, you can't help that,' said the Cat: 'we're all mad here. I'm mad. You're mad.'"; var matches = Regex.Matches(text, @"\w+[^\s]*\w+|\w"); foreach (Match match in matches) { var word = match.Value; } 

我相信这是最短的RegEx,可以得到所有的话

 \w+[^\s]*\w+|\w 

如果你不想使用Regex对象,你可以做类似……

 string mystring="Oh, you can't help that,' said the Cat: 'we're all mad here. I'm mad. You're mad."; List words=mystring.Replace(",","").Replace(":","").Replace(".","").Split(" ").ToList(); 

你仍然需要在“那个”结尾处理尾随撇号。

这是解决方案之一,我不使用任何帮助程序类或方法。

  public static List ExtractChars(string inputString) { var result = new List(); int startIndex = -1; for (int i = 0; i < inputString.Length; i++) { var character = inputString[i]; if ((character >= 'a' && character <= 'z') || (character >= 'A' && character <= 'Z')) { if (startIndex == -1) { startIndex = i; } if (i == inputString.Length - 1) { result.Add(GetString(inputString, startIndex, i)); } continue; } if (startIndex != -1) { result.Add(GetString(inputString, startIndex, i - 1)); startIndex = -1; } } return result; } public static string GetString(string inputString, int startIndex, int endIndex) { string result = ""; for (int i = startIndex; i <= endIndex; i++) { result += inputString[i]; } return result; } 

您可以尝试使用正则表达式删除未被字母(即单引号)包围的撇号,然后使用Char静态方法去除所有其他字符。 首先调用正则表达式,你可以保留收缩撇号(例如can't ),但删除单引号,如'Oh

 string myText = "'Oh, you can't help that,' said the Cat: 'we're all mad here. I'm mad. You're mad.'"; Regex reg = new Regex("\b[\"']\b"); myText = reg.Replace(myText, ""); string[] listOfWords = RemoveCharacters(myText); public string[] RemoveCharacters(string input) { StringBuilder sb = new StringBuilder(); foreach (char c in input) { if (Char.IsLetter(c) || Char.IsWhiteSpace(c) || c == '\'') sb.Append(c); } return sb.ToString().Split(' '); }