使用Json.NET反序列化复杂对象

我需要反序列化从grogle maps api返回的这个json：

{ "destination_addresses": [ "Via Medaglie D'Oro, 10, 47121 Forlì FC, Italia", "Via Torino, 20123 Milano, Italia", "Via Guglielmo Marconi, 71, 40121 Bologna, Italia", "Via Irnerio, 40126 Bologna, Italia" ], "origin_addresses": [ "Via Medaglie D'Oro, 10, 47121 Forlì FC, Italia", "Via Torino, 20123 Milano, Italia", "Via Guglielmo Marconi, 71, 40121 Bologna, Italia", "Via Irnerio, 40126 Bologna, Italia" ], "rows": [ { "elements": [ { "distance": { "text": "1 m", "value": 0 }, "duration": { "text": "1 min", "value": 0 }, "status": "OK" }, { "distance": { "text": "286 km", "value": 286281 }, "duration": { "text": "2 ore 48 min", "value": 10083 }, "status": "OK" }, { "distance": { "text": "80,1 km", "value": 80088 }, "duration": { "text": "1 ora 3 min", "value": 3789 }, "status": "OK" }, { "distance": { "text": "77,6 km", "value": 77594 }, "duration": { "text": "57 min", "value": 3422 }, "status": "OK" } ] }, { "elements": [ { "distance": { "text": "288 km", "value": 287811 }, "duration": { "text": "2 ore 48 min", "value": 10052 }, "status": "OK" }, { "distance": { "text": "1 m", "value": 0 }, "duration": { "text": "1 min", "value": 0 }, "status": "OK" }, { "distance": { "text": "212 km", "value": 212423 }, "duration": { "text": "2 ore 8 min", "value": 7664 }, "status": "OK" }, { "distance": { "text": "218 km", "value": 218219 }, "duration": { "text": "2 ore 9 min", "value": 7740 }, "status": "OK" } ] }, { "elements": [ { "distance": { "text": "78,5 km", "value": 78528 }, "duration": { "text": "56 min", "value": 3346 }, "status": "OK" }, { "distance": { "text": "212 km", "value": 212190 }, "duration": { "text": "2 ore 5 min", "value": 7519 }, "status": "OK" }, { "distance": { "text": "1 m", "value": 0 }, "duration": { "text": "1 min", "value": 0 }, "status": "OK" }, { "distance": { "text": "2,0 km", "value": 1979 }, "duration": { "text": "5 min", "value": 316 }, "status": "OK" } ] }, { "elements": [ { "distance": { "text": "74,7 km", "value": 74719 }, "duration": { "text": "55 min", "value": 3278 }, "status": "OK" }, { "distance": { "text": "218 km", "value": 217951 }, "duration": { "text": "2 ore 9 min", "value": 7712 }, "status": "OK" }, { "distance": { "text": "3,8 km", "value": 3782 }, "duration": { "text": "11 min", "value": 671 }, "status": "OK" }, { "distance": { "text": "1 m", "value": 0 }, "duration": { "text": "1 min", "value": 0 }, "status": "OK" } ] } ], "status": "OK" } 

我需要创建一个距离矩阵，所以我只对“距离”内的“值”字段感兴趣。

我尝试过这种方法：

 DataSet data = JsonConvert.DeserializeObject(jsonResponse); DataTable dataTab = data.Tables["Elements"]; foreach (DataRow elements in dataTab.Rows) { Console.WriteLine(elements["distance"]); //Do something else here } 

但是JSonConvert返回“完成反序列化对象后在JSON字符串中找到的附加文本”。

Answer 1

您应该反序列化到与您的数据匹配的类。 您可以在http://json2csharp.com/上生成这些类。

 // use like var rootObj = JsonConvert.DeserializeObject(jsonResponse); foreach (var row in rootObj.rows) { foreach (var element in row.elements) { Console.WriteLine(element.distance.text); } } // you might want to change the property names to .Net conventions // use [JsonProperty] to let the serializer know the JSON names where needed public class Distance { public string text { get; set; } public int value { get; set; } } public class Duration { public string text { get; set; } public int value { get; set; } } public class Element { public Distance distance { get; set; } public Duration duration { get; set; } public string status { get; set; } } public class Row { public List elements { get; set; } } public class RootObject { public List destination_addresses { get; set; } public List origin_addresses { get; set; } public List rows { get; set; } public string status { get; set; } } 

Answer 2

我相信这个问题是基于我在搜索Stack Overflow时发现的类似问题的’DataSet’。

尝试这个，因为我相信它会起作用（你可能需要使用’rows’而不是’Elements’，但我相信使用JObject的方法将解决’附加文本’的主要问题。

  JObject json = JsonConvert.DeserializeObject(jsonResponse); foreach (Dictionary item in data["Elements"]) { foreach (string val in item.Values) { Console.WriteLine(val); } } 

Answer 3

使用动态：

 dynamic json = JsonConvert.DeserializeObject(jsonResponse); var rowCount = json.rows.Count; Func getElementCount = r => r.elements.Count; var maxElements = Enumerable.Max(json.rows, getElementCount); var matrix = new int?[rowCount, maxElements]; for(int i = 0; i < rowCount; i++) { var elements = json.rows[i].elements; for(int j = 0; j < elements.Count; j++) { var element = elements[j]; matrix[i, j] = element.distance.value; } }