如何断言方法具有指定的属性

是否可以将解决方案概括为适用于任何类型？

有一个很好的解决方案来断言方法上是否存在指定的属性：

public static MethodInfo MethodOf( Expression expression ) { MethodCallExpression body = (MethodCallExpression)expression.Body; return body.Method; } public static bool MethodHasAuthorizeAttribute( Expression expression ) { var method = MethodOf( expression ); const bool includeInherited = false; return method.GetCustomAttributes( typeof( AuthorizeAttribute ), includeInherited ).Any(); } 

用法如下：

  var sut = new SystemUnderTest(); var y = MethodHasAuthorizeAttribute(() => sut.myMethod()); Assert.That(y); 

我们如何推广此解决方案并更改签名：

 public static bool MethodHasAuthorizeAttribute(Expression expression) 

这样的事情：

 public static bool MethodHasSpecifiedAttribute(Expression expression, Type specifiedAttribute) 

是否可以将解决方案概括为适用于任何类型？

Answer 1

 public static MethodInfo MethodOf(Expression expression) { MethodCallExpression body = (MethodCallExpression)expression.Body; return body.Method; } public static bool MethodHasAttribute(Expression expression, Type attributeType) { var method = MethodOf(expression); const bool includeInherited = false; return method.GetCustomAttributes(attributeType, includeInherited).Any(); } 

或者使用generics：

 public static bool MethodHasAttribute(Expression expression) where TAttribute : Attribute { var method = MethodOf(expression); const bool includeInherited = false; return method.GetCustomAttributes(typeof(TAttribute), includeInherited).Any(); } 

您可以这样称呼：

 var sut = new SystemUnderTest(); y = MethodHasAttribute(() => sut.myMethod()); That(y);